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mamaluj [8]
2 years ago
8

Please help I’ll give brainliest if I can :)

Mathematics
1 answer:
denis23 [38]2 years ago
5 0
57.3333 the three is infinite
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What is the area of a circle whose radius is 4 ft?
ExtremeBDS [4]

Answer:

16π ft²

Step-by-step explanation:

The formula is [ A = πr² ]

A = π(4)²

A = 16π

Best of Luck!

6 0
3 years ago
If x = 45, then<br> is between_<br> 4 and 5<br> 6 and 7<br> 22 and 23<br> 44 and 46
MrRa [10]
Im confused on what your trying to ask...
6 0
3 years ago
Mr. Cooper is making homework packets. He will put 6 worksheets in each packet. There are 18 worksheets. How many packets can he
ziro4ka [17]

6 times 18

Answer is 108

8 0
3 years ago
-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




4 0
3 years ago
Please help w/ this question <br><br> image attached
vovikov84 [41]

It is A I vsnududuudududu


3 0
3 years ago
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