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mamaluj [8]
2 years ago
8

Please help I’ll give brainliest if I can :)

Mathematics
1 answer:
denis23 [38]2 years ago
5 0
57.3333 the three is infinite
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Solve this identifying holes, vertical asymptotes, and horizontal asymptotes for
USPshnik [31]

x^2+7x+12=x^2+4x+3x+12=x(x+4)+3(x+4)=(x+4)(x+3)\\\\-x^2-3x+4=-(x^2+3x-4)=-(x^2+4x-x-4)\\\\=-[x(x+4)-1(x+4)]=-(x+4)(x-1)\\\\f(x)=\dfrac{x^2+7x+12}{-x^2-3x+4}=\dfrac{(x+4)(x+3)}{-(x+4)(x-1)}\\\\\text{Vertical asymptotes:}\\\\(x+4)(x-1)=0\iff x+4=0\ \vee\ x-1=0\\\\\boxed{x=-4\ and\ x=1}\\\\\text{Horizontal asymptotes:}

\lim\limits_{x\to\pm\infty}\dfrac{x^2+7x+12}{-x^2-3x+4}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\dfrac{7}{x}+\dfrac{12}{x^2}\right)}{x^2\left(-1-\dfrac{3}{x}+\dfrac{4}{x^2}\right)}=\dfrac{1}{-1}=-1\\\\\boxed{y=-1}

6 0
3 years ago
What is 43.09 to the nearest whole number​
Svetach [21]

Answer:

43

Step-by-step explanation:

  • 43.09 has 2 parts the integer part which is basically to the left and the decimal point which is to the right. to get this to the nearest integer or whole number you would have to round it off so you only have the integer part to do so the first digit in the fractional part is less than 5 then simply remove the fractional part to get the answer but in this case the de
6 0
3 years ago
Suppose you have the following recursion formula a1 = 1, a2 = 2, and an = a(n - 1)+ a(n - 2)for integers n ≥ 3. How would you de
julia-pushkina [17]
A3=3
a4=5
a5=8

This sequence has properties similar to those of the Fibonacci sequence.
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3 years ago
When a photo is reduced or enlarged, its length to width ratio usually remains the same. Aurelia wants to enlarge a 4-inch by 6-
Nikitich [7]
\sf \frac{4}{6} = \frac{x}{15} \\4(15) = 6x\\6x = 60\\x = 10\\\\So~the~new~dimensions~are~10~inches~by~15~inches
6 0
3 years ago
Evaluate 3x^3 - 5y^2 x=5 y=2
Sliva [168]

Answer:

355

Step-by-step explanation:

3x^{3}-5y^{2}=3*5³-5*2²

3*5³-5*2²=3*125-5*4

3*125-5*4=375-20

375-20=355

6 0
3 years ago
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