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rosijanka [135]
2 years ago
12

Please help me understand

Mathematics
2 answers:
ella [17]2 years ago
5 0

Answer:

  yes

Step-by-step explanation:

The offered ordered pair is a solution if those x- and y-values satisfy both equations. Let's check:

  9x +y = 10

  9(1) +(1) = 9 +1 = 10 . . . . true

__

  6x +5y = 11

  6(1) +5(1) = 6 +5 = 11 . . . . true

__

The ordered pair (x, y) = (1, 1) satisfies both equations, so (1, 1) is a solution to this system.

galina1969 [7]2 years ago
5 0

\huge\bf\underline{\underline{\pink{A}\orange{N}\blue{S}\green{W}\red{E}\purple{R:-}}}

1) Placing (1,1) in equation 9x + y = 10

:\implies\tt{9(1) + 1 = 10} \\  \\ :\implies\tt{9 + 1 = 10} \\  \\ :\implies\tt{10 = 10} \\  \\ :\implies\tt{lhs = rhs}

2) Placing (1,1) in equation 6x + 5y = 11

:\implies\tt{6(1) + 5(1) = 11} \\  \\ :\implies\tt{6 + 5 = 11} \\  \\ :\implies\tt{11 = 11} \\  \\ :\implies\tt{lhs = rhs}

  • Thus, the ordered pair (x,y) = (1.1) satisfies both the equations so it is solution to the given system.
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Step-by-step explanation:

Given the function

f\left(x\right)\:=\:\left(x-5\right)^3-1

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switch sides

\left(x-5\right)^3-1=-3

Add 1 to both sides

\left(x-5\right)^3-1+1=-3+1

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\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

Thus, the input values are:

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And the real input is:

x=-\sqrt[3]{2}+5

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3 years ago
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