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ELEN [110]
3 years ago
11

I will give thanks and five stars to the person that helps me.

Mathematics
1 answer:
pentagon [3]3 years ago
8 0

Answer:

Third option is correct!

Step-by-step explanation:

x+19<28

or, x<9

so

x = {3,4,5,6}

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Step-by-step explanation:

6 0
3 years ago
If I start at 327 how do I get to finish if I have to color in numbers divisible by six
9966 [12]
Try a calculator and doing some googling of numbers divisible by six. There's a great calculator site called calculator soup! ( Yes it's really called calculator soup )
3 0
3 years ago
Write the sentence as an equation <br>the sum of m and 188 is 232​
Oksanka [162]

Hey there! Your equation would be m + 188 = 232

5 0
3 years ago
6x-2y=24<br> how do u solve for y
Tatiana [17]
It's <span>Diophantine equation. 
First, we need to found gcd(6,(-2)):</span>
6=2*3
(-2)=(-1)*2

So, gcd(6,-2)=2
Now, the question is. Can we dived c=24, by gcd(6,-2) and in the end get integer?
Yes we can.
\frac{24}{2} =12
So, we can solve it.

Now is the formula:
{\displaystyle {\begin{cases}x=x_{0}+n{\frac {b}{\gcd(a,\;b)}}\\y=y_{0}-n{\frac {a}{\gcd(a,\;b)}}\end{cases}}\quad n\in \mathbb {Z} .}

Second, we need the first pair (x0,y0) 
 if
x=0
then
y=(-12)

Third, we gonna use that formula:
{\displaystyle {\begin{cases}x=-n}\\y=-3(4+n)}\end{case}\quad n\in \mathbb {Z} .}
Congratulations! We solve it.


8 0
3 years ago
Read 2 more answers
Ms. Lunette has 18 students in her class. She wants to send 3 of these students to pick up books for the class.
tigry1 [53]

The number of possible combinations is given by

... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations

_____

There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.

7 0
3 years ago
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