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xenn [34]
2 years ago
14

The counting number ABAB is a multiple of 36. If different letters represent different digits, what is the greatest value ABAB c

an have? PLS HELP ONLY 10 minutes
Mathematics
1 answer:
almond37 [142]2 years ago
6 0

The greatest value ABAB can have is 7272.

The given parameters:

  • <em>Counting number ABAB = multiple of 36</em>

The counting number can be expanded as follows;

ABAB = 100 x AB  + AB

          = AB00 + AB

          = AB(100 + 1)

          = AB(101)

101 is a prime factor of AB and has only two factors.

The prime factor of 101 = 1 x 2

Since 101 is prime, the counting number AB must 2-digits multiples of 36.

The greatest value ABAB can have is calculated as follows;

ABAB = (36 x 2)(36 x 2)

ABAB = 7272

Thus, the greatest value ABAB can have is 7272.

Learn more about prime factors here:  brainly.com/question/24612438

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3 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
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jenyasd209 [6]

Answer:

192

Step-by-step explanation:

both triangles are 12 in and the square is 168

so 12+12+168= 192in

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3 years ago
Evaluate Functions<br> Given f(x) = 2x + 6 and g(x) = 5x - 1<br> Evaluate f(-2)
ZanzabumX [31]

Answer:

f(-2) = -4x + 6

Step-by-step explanation:

f(x) = 2x + 6

f(-2) = -2(2x) + 6

f(-2) = -4x + 6

4 0
3 years ago
Read 2 more answers
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