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1 year ago

What temperature are 22.7 degrees colder than 96.5 degrees?

Mathematics

2 answers:

Gwar [14]1 year ago

4 0

Answer:

73.8º

Step-by-step explanation:

96.5-22.7=

73.8º

Dominik [7]1 year ago

4 0

Answer:

73.8 F

Step-by-step explanation:

96.5-22.7

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Sergeu [11.5K]

Answer:

-4

Step-by-step explanation:

7 0

2 years ago

Whixh list of numbers is ordered from least to greatest?

Rzqust [24]

Answer:

B is the solution

Step-by-step explanation:

-6.53 is the furthest from 0

-6 1/4 is closer to 0

6.57 is positive and more than 0

6 3/4 is also positive and more than 6.57

8 0

7 months ago

If the simple interest on $6,000 for 9 years is $3,240 , then what is the interest rate?

igor_vitrenko [27]

Rate of interest is 6 %

Solution:

Given in question that,

simple interest = $ 3240

number of years = 9 years

principal sum = $ 6000

To find: interest rate

The simple interest is given as:

$S.I = \frac{pnr}{100}$

Where, "p" is the principal

"r" is the rate of interest

"n" is the number of years

Substituting the values in above formula,

$3240 = \frac{6000 \times 9 \times r}{100}\\\\3240 = 60 \times 9 \times r\\\\3240 = 540 \times r\\\\r = \frac{3240}{540}\\\\r = 6$

Thus rate of interest is 6 %

8 0

2 years ago

Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by: