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iogann1982 [59]
3 years ago
13

Krystal can wax a floor in 16 minutes. Perry helped her and it took 5.76 minutes. How long would it take perry to do it alone?

Mathematics
1 answer:
finlep [7]3 years ago
8 0
<span>Krystal's rate = 1 floor in 16 min. = 1/16 floors per min.

Working together their rate = 1 floor in 5.76 min. = 1/5.76 floors per min.

We need to determine Perry's rate, so we need to equate their combined rate with the sum of the individual rates.

Let Perry's time = x

In equation form, we can write:
1/16 + 1/x = 1/5.76
Solve for x:

(x+16)/16x = 1/5.76 -> 5.76(x+16) = 16x -> 10.24x = 92.16 -> x = 9

So, Perry would take 9 mins. to do the floor alone.

I hope this helped!
Please Rate & Thank!
Please mark as Brainliest!

Have a wonderful night! : )</span>
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never [62]

Answer:

Part A: α = arc tan (y/x) = tan⁻¹ (y/x)

Part B: quadrant II α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 180°>α>90°

            quadrant III α = arc tan (-y)/(-x) = arc tan (y/x) = tan⁻¹ (y/x) 270°>α>180°

            quadrant IV α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 360°>α>270°

Part C: quadrant II 180°>α>90°  α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 180° - 80.53° = 99.47°

Step-by-step explanation:

PART A:

In this case we will use trigonometric function tanα to calculate angle α:

tanα = y/x => α = arc tan (y/x) = tan⁻¹ (y/x)

This formula is use in general way and in first quadrant  90°>α>0°

Part B:

But in the other quadrants you must know to use unit circle to reduce angle from II, III and IV quadrant to the first quadrant.

If angle is in the quadrant II  180°>α>90° then

tanα = - tan (180°-α)

If angle is in the quadrant III  270°>α>180° then

tanα = tan (α-180°)

If angle is in the quadrant IV  360°>α>270° then

tanα =- tan (360°-α)

Part C:

vector w (x,y) = (-1,6) this vector lies in quadrant II      180°>α>90°

180°- α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 80.53°  => 180° - α = 80.53°

α = 180° - 80.53 = 99.47°

It's not easy to understand this, but it's not easy for me to explain.

God with you!!!

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