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iogann1982 [59]
3 years ago
13

Krystal can wax a floor in 16 minutes. Perry helped her and it took 5.76 minutes. How long would it take perry to do it alone?

Mathematics
1 answer:
finlep [7]3 years ago
8 0
<span>Krystal's rate = 1 floor in 16 min. = 1/16 floors per min.

Working together their rate = 1 floor in 5.76 min. = 1/5.76 floors per min.

We need to determine Perry's rate, so we need to equate their combined rate with the sum of the individual rates.

Let Perry's time = x

In equation form, we can write:
1/16 + 1/x = 1/5.76
Solve for x:

(x+16)/16x = 1/5.76 -> 5.76(x+16) = 16x -> 10.24x = 92.16 -> x = 9

So, Perry would take 9 mins. to do the floor alone.

I hope this helped!
Please Rate & Thank!
Please mark as Brainliest!

Have a wonderful night! : )</span>
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Distance between Station E  and Station G  is 8.48 miles (Approx.)

<u>Given:</u>

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<u>Find:</u>

Distance between Station E  and Station G

<u>Computation:</u>

Co-ordinate of Point E = (-3 , 1)

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So,

Co-ordinate of Point G = (3 , -5)

Distance between two point = √(x2 - x1)² + (y2 - y1)²

So,

Distance between Station E  and Station G  = √(3 + 3)² + (-5 - 1)²

Distance between Station E  and Station G  = √(6)² + (-6)²

Distance between Station E  and Station G  = √36 + 36

Distance between Station E  and Station G  = √72

Distance between Station E  and Station G  = 8.48 miles (Approx.)

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2 years ago
In a recent year, team 1 made 191 out of 238 free- throw attempts and team 2 made 106 out of 160 free- throw attempts. Copy and
ivann1987 [24]
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2x^2 + 3x - 12 when x = 5 help pls
cluponka [151]

\huge\textsf{Hey there!}

\mathsf{2x^2 + 3x - 12}

\mathsf{= 2(5)^2 + 3(5) - 12}

\mathsf{5^2}

\mathsf{= 5 \times 5}

\mathsf{\bf = 25}

\mathsf{2(25) + 3(5) - 12}

\mathsf{2(25)}

\mathsf{= \bf 50}

\mathsf{3(5)}

\mathsf{= \bf 15}

\mathsf{= 50 + 15 -  12}

\mathsf{50 + 15}

\mathsf{= \bf 65}

65 - 12

\mathsf{= \bf 53}

\boxed{\boxed{\huge\textsf{Answer: \bf 53}}}\huge\checkmark

\large\textsf{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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3 years ago
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If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

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Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

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Therefore;

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m∠SQT = 71°

m∠PQT = 2 × m∠SQT

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m∠PQT = 142°

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m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

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