the graph of y=e^tanx-2 crosses the x axis at one point in the interval [0,1]. What is the slope of the graph at this point? I g
et 3.08267 but it's not the right answer
1 answer:
Y = e^tanx - 2
To find at which point it crosses x axis we state that y= 0
e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061
to find slope at that point first we need to find first derivative of funtion y.
y' = (e^tanx)*1/cos^2(x)
now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
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The answer to the question

This happens for

and

where

is any integer.
A' (1,4)
B' (5,8)
C' (5,4)
D' (4,2)
Answer:
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Step-by-step explanation:
90% of 50 is 45 so the answer is 45