To solve this problem you must apply the proccedure shown below:
1. The problem asks for the area of a cross section that is parallel <span>to face ABCD. As is parallel to that face, you have can calculate its area as following:
A=12 cm x 6 cm
2. Therefore, the result is:
A=72 cm</span>²
The answer is: T<span>he area of a cross section that is parallel to face ABCD is 72 cm</span>².
The height of the kite above the ground is 58.68 ft
Let x be the height of the kite above Chee's hand.
The height of the kite above Chee's hand, the string and the horizontal distance between Chee and the kite form a right angled triangle with hypotenuse side, the length of the string and opposite side the height of the kite above Chee's hand.
Since we have the angle of elevation from her hand to the kite is 29°, and the length of the string is 100 ft.
From trigonometric ratios, we have
tan29° = x/100
So, x = 100tan29°
x = 100 × 0.5543
x = 55.43 ft.
Since Chee's hand is y = 3.25 ft above the ground, the height of the kite above the ground, L = x + y
= 55.43 ft + 3.25 ft
= 58.68 ft to the nearest hundredth of a foot
So, the height of the kite above the ground is 58.68 ft
Learn more about height of kite above the ground here:
brainly.com/question/14350740
8-4x=0
-4x=-8
x=2
you mean like this?
The ratio 21:14 when divided by 7 on each side, is the smallest ratio that has the same value as 21:14. this becomes 3:2
then multiply both sides by a few different numbers on both sides each ,
for example, 3:2 is the same as
6:4 (3:2 times 2)
9:6 (3:2 times 3)
12:8 (3:2 times 4)
15:10 (3:2 times 5) and so on
the ratio of the right number I
divided by the left on all of them is 1.5
so,
14/10 equals 1.4 (nope)
8/4 equals 2 (nope)
9/6 equals 1.5 (yay)
12/21 equals 0.57 (Lol)
So your answer is 9:6
Here you go! Hope this helps!!!