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julia-pushkina [17]

2 years ago

7

Each child in the Martin family decided to save money for the family vacation.

1 answer:

irinina [24]2 years ago

5 0

Answer:

The story is not clear enough to provide the answer

Step-by-step explanation:

First of all we do not know how many childen are in the Martin Family

$20 \times 8$

=$160

So depending on how each child sends and how many children will determine which kid will have most of the money left

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hoa [83]

I agree the answer is B I think so

4 0

3 years ago

Write an equivalent expression for 7¹² × 7⁴

ira [324]

Answer:

$\huge\boxed{7^{16}}$

Step-by-step explanation:

We can use exponent rules to try and simplify this expression down.

Exponent rules tell us that $x^a + x^b = x^{a+b}$ .

This means that since we have the same base on both terms (7 and 7), we can add the exponents to get a simplified expression.

$12 + 4 = 16$

So our simplified expression is $7^{16}$ .

Hope this helped!

7 0

3 years ago

When the members of a family discussed where their annual reunion should take place, they found that out of all the family mem

Doss [256]

Answer:

The total number of family members is 21.

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of these sets.

I am going to say that:

-The set A represents those that would not go to a park.

-The set B represents those who would not go to a beach.

-The set C represents those who would not go to the family cottage.

The value d represents those who would go to all three places.

We have that:

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

In which a are those that would only not go to a park, $A \cap B$ are those who would not got to a park or to the beach, $A \cap C$ are those who would not go to a park or to the famili cottage. And $A \cap B \cap C$ are those that would not go to any of these places.

By the same logic, we have:

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

This diagram has the following values:

$a,b,c,d,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)$

The total number of family members is the sum of all these values:

$T = a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

We start finding the values from the intersection of the three sets

5 would not go to a park or a beach or to the family cottage.

This means that $A \cap B \cap C = 5$

1 would go to all three places. This means that $d = 1$ .

8 would go to neither a park nor the family cottage

This means that:

$A \cap C + (A \cap B \cap C) = 8$

$A \cap C = 3$

8 would go to neither a beach nor the family cottage

$B \cap C + (A \cap B \cap C) = 8$

$B \cap C = 3$

7 would go to neither a park nor a beach

$A \cap B + (A \cap B \cap C) = 7$

$A \cap B = 2$

15 would not go to the family cottage

$C = 15$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

$15 = c + 3 + 3 + 5$

$c = 4$

12 would not go to a beach

$B = 12$

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$12 = b + 3 + 2 + 5$

$b = 2$

11 would not go to a park

$A = 11$

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

$11 = a + 2 + 3 + 5$

$a = 1$

Now, we can find the total number of family members.

$T = a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

$T = 1 + 2 + 4 + 1 + 2 + 3 + 3 + 5$

$T = 21$

The total number of family members is 21.

5 0

3 years ago

Need help please someone answer quick

Leya [2.2K]

Answer:

2x/19

Quotient = division

Product = multiplication

Difference = subtraction

Sum = addition

6 0

2 years ago

Round 6.81 to the nearest tenth

zhenek [66]

6.8 is the answer!!!!

8 0

3 years ago