Answer:
the probability that a sample of 4 bags will have a mean weight less than 9.8 pounds is 0.05
Step-by-step explanation:
Given the data in the question;
μ_x = 10 pound bags
standard deviation s_x = 0.24 pounds
sample size n = 4
The bag weights are normally distributed so;
p( x' less than 9.8 ) will be;
p( (x'-μ_x' / s_x') < (9.8-μ_x' / s_x') )
we know that;
μ_x' = μ_x = 10
and s_x' = s_x/√n = 0.24/√4
so; we substitute
p( z < ( (9.8 - 10) / (0.24/√4) )
p( z < -0.2 / 0.12 )
p( z < -1.67 )
{ From z-table }
⇒ p( z < -1.67 ) = 0.0475 ≈ 0.05
Therefore, the probability that a sample of 4 bags will have a mean weight less than 9.8 pounds is 0.05
Answer:
34175 people will live in Pattersonville 8 years from now
Step-by-step explanation:
Initial population of Pattersonville =40,500
We are given that The census indicated that the population of the town has been decreasing by 2.1% per year .
Now we are supposed to find If this trend continues , approximately how many people will live in Pattersonville 8 years from now
Formula : 
Where N(t)= Population after t years
= Initial population
r = rate of decrease = 2.1 %=0.021
t = 8 years
Substitute the values in the formula :
So,
N(8)=34175.63223
So, 34175 people will live in Pattersonville 8 years from now
Use Pemdas
<span>76-183+56-1,543
</span><span>-107+56-1,543
</span><span>-51-1,543
</span>−<span>1594
</span>
−1594<span> is your answer.
</span>
Hoped I helped!
Answer:
(y-(-3))=4(x-(-1))
Step-by-step explanation:
formula for point slope form is:
y-y1=m(x-x1)
just plug in numbers from the point (-1, -3) for x1 and y1. The slope 4, would plug into m.
Answer:
12
Step-by-step explanation:
hope it helps