Help plzzzzzzzzzzzzz

PLS HELP ME ITS DUE AT 12 AM I WILL GIVE THAT BRAINLY THING

Eduardwww [97]

9514 1404 393

Answer:

1. HA is equivalent to AAS when the triangle is a right triangle.

2. AM = BM, so the triangles are congruent by HL. CPCTC

3. The triangles are congruent by HL. CPCTC

Step-by-step explanation:

1. The acute angle of the triangle together with the right angle comprise two angles of the triangle. When two corresponding angles and a corresponding side (the side opposite the right angle) are congruent, the right triangles are congruent by the AAS theorem. (This can be referred to as the HA theorem.)

__

2. CM = DM; MA = MB; ∠A = ∠C = 90°, so all of the requirements for the HL theorem are met. ΔCMA ≅ ΔDMB, so AC ≅ BD by CPCTC.

__

3. TS = TV, TR = TR, ∠S = ∠V = 90°, so all requirements for the HL theorem are met. ΔTSR ≅ ΔTVR, so RS ≅ RV by CPCTC.

4 0

3 years ago

A political polling organization wishes to select a smaller focus group from a group of 7 Republicans, 10 Democrats, and 2 Indep

Alina [70]

Answer:

a) 1470 ways

b) 2835 ways

Step-by-step explanation:

the question is not correct, in the correct question The number of independents should be 3 not 2

there are 7 republicans, 10 democrats and 3 independents.

C(n,r) is the number of different combinations of n distinct objects taken r at a time.

C(n,r) = $\frac{n!}{(n-r)!r!}$

a) it will consist of 1 Republican and 4 Democrats

The number of ways this can be chosen is = C(7,1) × C(10,4) = $\frac{7!}{(7-1)!1!} * \frac{10!}{(10-4)!4!}$ = 7 × 210 = 1470 ways

(b) it will consist of 2 Republicans, 2 Democrats, and 2 Independents (consist of 2 independents not 3)

The number of ways this can be chosen is = C(7,2) × C(10,2) × C(2,2)

= $\frac{7!}{(7-2)!2!} * \frac{10!}{(10-2)!2!}* \frac{3!}{(3-2)!2!}$ = 21 × 45 × 3 = 2835 ways

7 0

3 years ago

Please hurry I need the answer

timama [110]

Answer:

4.12

Step-by-step explanation:

A^2+b^2=c^2 so 8^2+b^2=9^2 so 64+b^2=81 so b^2=17 so b=4.12

7 0

3 years ago

Which of the following sets of lengths could not be the side lengths of a triangle?

docker41 [41]

To find out if the three side lengths can create a triangle, the three smaller lengths must be greater than the longer length.

$\bf~Option~A$

$\sf~3~meters,5~meters,7~meters$

$\sf3+5=8>7$

So this can create a triangle.

$\bf~Option~B$

$\sf1~yard,1.25~yards,1.5~yards$

$\sf1+1.25=2.25>1.5$

So this can create a triangle.

$\bf~Option~C$

$\sf5~inches,10.5~inches,17~inches$

$\boxed{\sf5+10.5=15.5$

So this cannot create a triangle.

$\bf~Option~D$

$\sf15~millimeters,18~millimeters,30~millimeters$

$\sf15+18=33>30$

So this can create a triangle.

Therefore, your answer is Option C.

8 0

3 years ago

The function y = 60x 1+0.625x models the moose population in a small New Hampshire forest over a period of time. What is a reaso

Nitella [24]

I think that the correct function in your question should be y = 60x⁻¹ + 0.625x.

With that said, the answer is A. <span>0 < x < ∞
By the process of trial and error of the choices, we can see that this choice satisfies the equation. Take note that y models moose population, so y should always be positive. </span>

4 0

3 years ago