I believe the 3rd answer down if the information you provided is correct
Squaring the sum on the top, rules out 1 and 2 (not squaring the 7 only)
then 4 times the difference. so I believe 4 (x-1) on the bottom.
Use the factor theorem to determine whether the first polynomial is a factor of the second polynomial x-3;2x^2-4x+30
x−3,2x^2−4x+30
E. no solution. hope this helps! :)
Answer:
(√366 - 3)/24
Step-by-step explanation:
Given the following:
cos∝ = √3/8 and sinβ = √3/3
Sin(∝-β) = sin∝cosβ - cos∝sinβ
Get sin∝
Since cos∝ = √3/8
adj = √3
hyp = 8
opp = √8² - (√3)²
opp = √64 - 3
opp = √61
Recall that sin∝ = opp/hyp
sin∝ = √61/8
Get cosβ
Since sinβ = √3/3
opp = √3
hyp = 3
adj =√3² - (√3)²
adj = √9-3
adj = √6
Recall that cosβ = adj/hyp
cosβ = √6/3
Substitute the gotten values into the formula
Sin(∝-β) = sin∝cosβ - cos∝sinβ
Sin(∝-β) = ( √61/8)(√6/3)- (√3/8)(√3/3)
Sin(∝-β) = √366/24 - √9/24
Sin(∝-β) = (√366 - 3)/24
Answer:
6
Step-by-step explanation:
divide 
into 
keep change flip
and we get 9/2 * 4/3 which gives us 3*2 = 6
