Ask question

Ask question

All categories

3 years ago

11

Josh sold 4 more boxes of candy for the school fundraiser than Jenny. The sum was 22 of the boxes they sold. How many boxes did

they each sell?

1 answer:

agasfer [191]3 years ago

7 0

22-4=18
18/2=9
Jenny sold 9 boxes and Josh sold 13 boxes

You might be interested in

In the movie Maverick, Bret Maverick worked to raise enough money to enter a card championship. Twenty players entered the tourn

Alex17521 [72]

500,000 divided by 20 equals 25,000

8 0

3 years ago

Read 2 more answers

Please answer the question now in two minutes

oksian1 [2.3K]

Answer:

Coordinates of point P is $(-14,3)$ .

Step-by-step explanation:

Given that mid point of line segment $\overline {PQ}$ is at <em>M(-9, 8.5).</em>

Q is at <em>(-4, 14)</em>.

Let coordinate of P be $(x,y)$ .

Using the ratio, we can say the following:

<em>The coordinates of mid point</em> $(X,Y)$ of a line with endpoints $(x_1, y_1)$ and $(x_2, y_2)$ is given as:

$X=\dfrac{(x_1+ x_2)}{2}$

$Y=\dfrac{(y_1+ y_2)}{2}$

Using the formula for above given dimensions:

$-9 =\dfrac{x+(-4)}{2}\\\Rightarrow x = -18+4 = -14$

$8.5=\dfrac{(14+ y)}{2}\\\Rightarrow y = 17-14 =3$

So, the <em>coordinates of point P are</em> $(-14,3)$ .

6 0

3 years ago

A straight angle has four angles. angle 1=39º, angle 2=54º, angle 3=48º, what is the measure of angle 4 ?

Ludmilka [50]

Answer:

39 degrees

Step-by-step explanation:

Add: 39+54+48=141

180 (degrees of a straight angle) minus 141=39

39 degrees

Hope I helped!! :)

Brainliest?!?!

Stay safe and have a good day/night/afternoon!!!

8 0

2 years ago

Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

X-1 is a factor of 4 + 5x2 - 4x2 - 8x+ 6.<br> O True<br> False

Marizza181 [45]

Answer:

False

Step-by-step explanation:

Bc I literally just took that quiz and it's false

6 0

3 years ago

Read 2 more answers