Answer:
B
Step-by-step explanation:
Also the answer must be under 9 so that rules out option D
Because We know CE = 2 and AD is visibly larger than CE, 6We can rule out option A
And that brings us down to B and C
CB is equal to 6, And I'm no genius, but I'm pretty sure AD is DEFINATLY not equal to 6.
so the answer is B
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
STEP
1
:
Equation at the end of step 1
((49 • (x2)) + 12xy) + 26y2
STEP
2
:
Equation at the end of step
2
:
(72x2 + 12xy) + 26y2
STEP
3
:
Trying to factor a multi variable polynomial
3.1 Factoring 49x2 + 12xy + 64y2
Try to factor this multi-variable trinomial using trial and error
Factorization fails
Final result :
49x2 + 12xy + 64y2
Answer:2:8 , 3:12, 4:16, 5:20
Step-by-step explanation:
Use the factor theorem to determine whether the first polynomial is a factor of the second polynomial x-3;2x^2-4x+30
x−3,2x^2−4x+30