All categories

3 years ago

Sam ran at 6km/h for 2h 20 mins. What distance did he run?

2 answers:

8 0

The trick Is to break it up 2 hours and 20 minutes and convert the 20 minute into hours, so if he runs at 6km/h then in 2 hours he ran 12 kms and 20 minutes in hours = 1/3 of hour therefore 6 multiplied by 1/3 is 2 km therefore th total he ran was 14 kms

HACTEHA [7]3 years ago

7 0

The distance that Sam ran is 14 km

You might be interested in

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2 y2 = (3x2 2y2 − x)2 (0,

inna [77]

X^2 + y^2 = (3x^2 + 2y^2 - x)^2
2x + 2y f'(x) = 2(3x^2 + 2y^2 - x)(6x + 4y f'(x) - 1) = 36x^3 + 24x^2yf'(x) + 24xy^2 + 16y^3f'(x) - 4y^2 - 18x^2 - 8xyf'(x) + x
f'(x)(2y - 24x^2y - 16y^3 + 8xy) = 36x^3 + 24xy^2 - 4y^2 - 18x^2 - x
f'(x) = (36x^3 + 24xy^2 - 4y^2 - 18x^2 - x)/(2y - 24x^2y - 16y^3 + 8xy)
f'(0, 0.5) = -4(0.5)^2/(2(0.5) - 16(0.5)^3) = -1/(1 - 2) = -1/-1 = 1

Let the required equation be y = mx + c; where y = 0.5, m = 1, x = 0
0.5 = 1(0) + c = 0 + c
c = 0.5

Therefore, the tangent line at point (0, 0.5) is
y = x + 0.5

3 0

3 years ago

Read 2 more answers

Apply the distributive property to produce an equivalent expression for 6(7 e + 3).

Ostrovityanka [42]

6(7e+3)= 42e+18 you multiple each thing within the parenthesis

7 0

3 years ago

Classify the quadrilateral. Then find the values of the variables.

lianna [129]

Trapezoid
Sides are congruent based on single hash marks on each.
Set equations equal to each other and solve.
5x - 1 = 3x + 5
Subtract 3x from both sides.
2x - 1 = 5
Add 1 to both sides.
2x = 6
Divide both sides by 2.
x = 3

6 0

3 years ago

Researchers suspect that 18% of all high school students smoke at least one pack of cigarettes a day. At the local high school,

Nataliya [291]

Answer:

We conclude that 18% of all high school students smoke at least one pack of cigarettes a day.

Step-by-step explanation:

We are given that researchers suspect that 18% of all high school students smoke at least one pack of cigarettes a day.

At the local high school, a randomly selected sample of 300 students found that 50 students smoked at least one pack of cigarettes a day.

Let p = <u><em>proportion of all high school students who smoke at least one pack of cigarettes a day.</em></u>

So, Null Hypothesis, $H_0$ : p = 18% {means that 18% of all high school students smoke at least one pack of cigarettes a day}

Alternate Hypothesis, $H_A$ : p < 18% {means that less than 18% of all high school students smoke at least one pack of cigarettes a day}

The test statistics that would be used here is <u>One-sample z -test for proportions</u> because we are given with the proportions values;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students who smoked at least one pack of cigarettes a day = $\frac{50}{300}$ = 0.167

n = sample of students = 300

So, <u><em>test statistics</em></u> = $\frac{0.167-0.18}{\sqrt{\frac{0.167(1-0.167)}{300} } }$

= -0.604

The value of z test statistics is -0.604.

Also, P-value of the test statistics is given to us is 0.2743.

Since, the P-value of test statistics is more than the level of significance as 0.2743 > 0.025, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that 18% of all high school students smoke at least one pack of cigarettes a day.

6 0

3 years ago

-2(-3v-5)-5v=12(1+v)-2

Alexandra [31]

<h3>Answer:</h3>

$\large\boxed{v=0}$

<h3>Step-by-step explanation:</h3>

In this question, we're solving the equation by figuring out what v equals to.

We are solving:

$-2(-3v-5)-5v=12(1+v)-2$

Solve:

$-2(-3v-5)-5v=12(1+v)-2\\\\\text{Distribute the -2 to the -3v and -5}\\\\6v+10-5v=12(1+v)-2\\\\\text{Distribute the 12 to the 1 and v}\\\\6v+10-5v=12+12v-2\\\\v+10=12+12v-2\\\\\text{Subtract both sides by 12v}\\\\-11v+10=12-2\\\\\text{Subtract both sides by 10}\\\\-11v=-10+12-2\\\\-11v=2-2\\\\-11v=0\\\\\text{Divide both sides by -11}\\\\\boxed{v=0}$

When you're done solving, you should get v = 0.

This means that v = 0 would be your final answer.

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>

8 0

4 years ago