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kobusy [5.1K]
3 years ago
14

Measuring the height of a tree is usually more difficult than measuring the diameter of the tree. Therefore, many researchers us

e regression models to predict the height of a tree from its diameter measured at 4 feet 6 inches from the ground. The following computer output shows the results of a linear regression based on the heights, in feet, and the diameters in inches, recorded from 31 felled trees.
Estimate Std Error t-value Pr(>|t|)
Intercept 62.031 4.383 14.15 0.0000
Diameter 1.054 0.322 0.0028 3.27
Which of the following is a 95 percent confidence interval for the slope of the population regression line?
(A) (0.001.2.107).
(B) (0.396, 1.712.
(C) (0.423,1.685).
(D) (0.732. 1.376).
(E) (53.07.70.99).
Mathematics
1 answer:
LenKa [72]3 years ago
8 0

Answer:

(B) (0.396, 1.712)

Step-by-step explanation:

From the information given;

Confidence Interval = 0.95

Significance Level = 1 - 0.95 = 0.05

The confidence interval for regression coefficient beta (whereby in this case it is the coefficient of the diameter) is expressed by:

= ( Beta ^- \ t_{n-2}, \alpha/2 ( S.E \ of \ \^ \ \ ), Beta^+ \ t_{n-2}, \alpha/2 ( S.E \ of \ \^ \ \ ))

From the regression coefficient, the estimated value of beta^  = 1.054

= (1.054 - t_{29,0.025} *(0.322), 1.054 + t_{29,0.025}*(0.322))

t_{229,0.025} = 2.0452\\\\ = \mathbf{(0.396, 1.712)}

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Jamie recently drove to visit her parents who live 510 miles away. On her way there her average speed was 25 miles per hour fast
tino4ka555 [31]

Answer:

       Average speed in mph with which he goes to parent's place = 75 mph

       Average speed with he comes back = 50 mph

Explanation:

  Distance between Jamie's house and parent's house = 510 miles.

  Let u be the average speed in mph with which he goes to their place.

  We have the average speed of coming back = (u -25) mph

  Total time of journey considering both ways = 17 hours.

  Time taken to go their home = 510/u hours

  Time taken for coming back = 510/(u-25) hours

  So total time = \frac{510}{u} +\frac{510}{u-25}

 Equating both times we have

       \frac{510}{u} +\frac{510}{u-25}=17\\ \\ 510u-12750+510u=17u^2-425u\\ \\ 17u^2-1445u+12750=0\\ \\ u^2-85u+750=0\\ \\ (u-75)(u-10)=0

  u = 75 mph or u =10 mph

If the average speed in mph with which he goes to their place = 75 mph, average speed with he comes back = 75-25 = 50 mph

If the average speed in mph with which he goes to their place = 75 mph, average speed with he comes back = 10-25 = -15 mph(Not possible)

So,  Average speed in mph with which he goes to parent's place = 75 mph

       Average speed with he comes back = 50 mph

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