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harina [27]
2 years ago
11

Sela's piano lesson starts at 4:45 pm. The lesson is 30 minutes long when does her lesson end.

Mathematics
1 answer:
zavuch27 [327]2 years ago
3 0

Answer:

her lesson ends at 5:15

Step-by-step explanation:

if you subtract 30 from 45 you get the time left over that will go toward the next hour (5 o'clock)

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F(x)= x^2 -16x+63 find the x-intercepts of this function
Ahat [919]

Answer:

The x-intercepts will be, x= 7 or x =9

Step-by-step explanation:

f(x)= x^2 -16x+63

At the x-intercept, f(x) is zero.

Therefore;

x² - 16x + 63 = 0

solving it quadratically;

product = 63

Sum       = -16

x² - 9x - 7x + 63 = 0

x(x-9) - 7( x-9) = 0

(x-7) (x-9) = 0

x = 7 or x = 9

Therefore;

The x-intercepts will be, x= 7 or x =9

8 0
3 years ago
Read 2 more answers
Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

6 0
3 years ago
Which shows a correct order to solve this story problem?
torisob [31]

you will have to do letter c witch was:

Step 1: Add the price of the tickets and the amount spent on food.
Step 2: Add the amount of the tax.
Step 3: Divide that total by 2.

3 0
3 years ago
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Mark spent 1 hour 17 minutes less than Sheila reading last week. Sheila spent 55 minutes less than Pete. Pete spent 3 hours read
Jlenok [28]

Mark spend 1 hour 10 minutes in reading.

<h3>What is Unitary Method?</h3>

Unitary method is a process by which we find the value of a single unit from the value of multiple units and the value of multiple units from the value of a single unit.

Mark spent 1 hour 17 minutes less than Sheila

Sheila spent 55 minutes less than Pete.

Pete spent 3 hours reading.

Since, pete spent 3 hours. So, Sheila spent

= 3 hours or (180 minutes) - 55 minutes

= 2 hours 05 minutes.

Now, Mark spent = 2 hrs 05 minutes - 55 minutes  

                            = 1 hour 10 minutes

Learn more about unitary method here:

brainly.com/question/22056199

#SPJ1

3 0
2 years ago
a telephone company charges a flat monthly fee of $22.00 for a telephone line and $0.20 per minute for long distance calls. If y
VikaD [51]
It will be 27 dollars
8 0
3 years ago
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