The y value of I is (5(2) + 3(5))/(3 + 5) = (10 + 15)/8 = 25/8 = 3.125
The main point which will immediately make it clear is that you have to plug in 2 for x so that you can find the linit. So, using this simple method you will get the <span>-1/4 answer. Hope you will agree with me and find this useful! Regards.</span>
Answer:
Every week, the mass of the sample is multiplied by a factor of 0.81
Step-by-step explanation:
Let's rewrite the base and find the expression whose exponent is just ttt.
(0.97)7t+5=(0.97)7t⋅(0.97)5=(0.977)t⋅(0.97)5
Therefore, we can rewrite the modeling function as follows.
M(t)=(0.97)5⋅(0.977)t
According to this model, the mass of the sample is multiplied by 0.977 every week. Rounding this to two decimal places, we get 0.977≈0.81.
Differentiating an integral removes the integral.
f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
38.50 = 100%
31.57 = ?
Multiply: 31.57 x 100 = 3,157
Divide: 3,157 ÷ 38.50 = 82%
100-82= 18% discount
