Asked and answered elsewhere.
brainly.com/question/1410592_____
Google doesn't recognize the terms "defects method" except in association with various postings of this same problem.
Answer:
24 units
Step-by-step explanation:
Given is a circle with two chord BE and CD
BE and CD intersect at A
By circle chords intersection theorem we have
DA*AC = EA*AB
i.e. 8(15) = 5(AB)
Divide by 5 both the sides
AB =8(15)/5 = 8(3) = 24 units
Verify:
Let us check now whether chord intersection theorem is satisfied.
DA*AC = 8(15) = 120
EA*AB = 5(24) = 120
Since these two equal, we verify that answer is right.
There is 10,000 possible combinations for the numbers 0-9
No, you cannot used that because you won't be able to solve that.
