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hammer [34]
3 years ago
6

62 = 9z + 17 Solve for Z

Mathematics
1 answer:
Lina20 [59]3 years ago
7 0

Answer : Z = 5

Step-by-step explanation :

62 = 9z + 17

-17 -17

45 = 9z

/9 /9

5 = z

Plug it back in :

62 = 9(5) + 17

62 = 45 + 17

62 = 62

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Answer:6

Step-by-step explanation:

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The science club is raising money for a trip to the museum. Tickets to the museum cost $8. Five students already have a membersh
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The answer is 42 students were in the club

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Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen
sergejj [24]

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

5 0
3 years ago
What is the common difference of the following sequence? 4.3,5,7,9,11___<br>5.16,19,22,25__​
myrzilka [38]

Answer:

Step-by-step explanation:

4). Given sequence → 3, 5, 7, 9, 11........

    Common difference of an arithmetic sequence is defined by,

    Common difference = Successive term - previous term

                                       = 2nd term - 1st term

                                       = 5 - 3

                                       = 2

5). Given sequence → 16, 19, 22, 25........

    Common difference of an arithmetic sequence = Second term - first term

                                                                                    = 19 - 16

                                                                                     = 3

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beks73 [17]
The person above me is right. It’s A , you have to add
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