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3 years ago

Estimate the quotient using front-end estimation.

Mathematics

2 answers:

Vladimir79 [104]3 years ago

7 0

Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat Meat

sveticcg [70]3 years ago

3 0

Answer:

12) 817 19. It becomes

800/20 = 40

13) 3615 72. It becomes

4000/70 = 57.1 = 60

14) 232 64. It becomes

200/60 = 33.3 = 30

15) 559 81. It becomes

600/80 = 7.5 = 8

16) 2986 222. It becomes

3000/200 = 15

17) 10275 232. It becomes

10000/200 = 50

18) 7428 286. It becomes

7000/300 = 23.3 = 20

19) 7143 369. It becomes

7000/400 = 17.5 = 18

20) 628,597 1525, it becomes

600000 - 2000 = 300

Step-by-step explanation:

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2 years ago

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3 years ago

the marks in an examination for a Physics paper have normal distribution with mean μ and variance σ2 . 10% of the students obtai

ipn [44]

Answer:

The mean of the distribution is about 53.9 and standard deviation is about 16.5 marks.

Step-by-step explanation:

Use the trick of transforming the given random variable one that is standard normal distributed, aka a z-score, then look up the two percentile values in z-score tables to get two equations with two unknowns.

So, let x be the variable describing the marks of a student, and

$z=(x-\mu)/\sigma$

the standardized equivalent of that (mu - mean, sigma - standard deviation).

We are looking for values of mu and sigma. At this point we'd be out of luck, but, wait, we're given two bits of info: the 10% point (aka, 90th percentile) and the 20% point (can be interpreted as 100-20th percentile). For each point we can use z-score tables to look up the corresponding values of z (just search for z tables). I found:

z-score for the 10% point: z_10=1.28

z-score for the 20% point: z_20=-0.84

That gives us two equations:

$z_{10}=1.28=(75-\mu)/\sigma\\z_{20}=-0.84=(40-\mu)\sigma$

and can be solved for mu and sigma (do the work on your end, I am showing my result):

$\mu=53.87\,\,,\,\, \sigma=16.51$

The mean of the distribution is about 53.9 and standard deviation is about 16.5 marks.

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3 years ago