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Elena L [17]
3 years ago
14

What is an equation of the line that is parallel to y = -5x + 6 and passes

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
3 0

Answer:

y=-5x-21  (D)

Step-by-step explanation:

Since the two lines parallel, their gradient must be equal

m1=m2=m=-5

y − y1 = m(x − x1)

And since the line passes trough pint (-4,-1), therefore

y –(-1) = -5(x – (-4))

y+1=-5(x+4)

y+1=-5x-20

y=-5x-20-1

y=-5x-21

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Will mark brainless
iren2701 [21]

Answer:

Step-by-step explanation:

y = 3x + 2

6x – 2y = 10

Ryan’s answer:

I solved by adding the equations. The solution is .

y = 3x + 2 → 3x + y = 2

6x – 2y = 10 → 3x – y = 5

6x = 7

x =

6x – 2y = 10 → 6 – 2y = 10

7 – 2y = 10

–2y = –3

y = -

Jesse’s answer:

I used matrices. The solution is .

Mark’s answer:

I graphed the equations. The lines are parallel and do not intersect, so there is no solution.

6 0
2 years ago
If i make 1.5 million dollars per day, plus an extra 250k interest every 31 hours, how much money do i make per day?
lidiya [134]

Answer: Alot

Step-by-step explanation:

4 0
2 years ago
Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
erastova [34]

Answer:

The probability is \frac{56!}{64!}

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 64 \choose 8 .

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}

7 0
2 years ago
4✓6 × 3✓6<br>multiply and simplify <br>show work​
mafiozo [28]

Answer:

3

√

2

Explanation:

First put change the words into an equation:

√

3

×

√

6

Now you can multiply them together as you would normally multiply:

√

3

×

√

6

=

√

18

Now let's prime factor 18 and see if there are any squares that we can take out of it to simplify. All we have to see is if there are 2 numbers that are the same:

18

/ \

6

3

/ \

2

3

As you can see, we have a square:

3

×

3

=

9

So take

√

9

out of

√

18

. You should have:

√

9

√

2

But since

√

9

=

3

we can simplify further to make:

√

9

√

2

→

3

√

2

Step-by-step explanation:

3 0
2 years ago
Could you help please..
Nitella [24]
Since she needs 3 1/2 for 5, and you need to find one batch, get 3 1/2 and divide it by 5. Change 3 1/2 to an improper fraction (7/2). Now use KCS (keep change switch) Keep the 7/2, change division to multiplication, and switch 5/1 to 1/5. (7/2)•(1/5)
4 0
2 years ago
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