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3 years ago

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Jasmine purchases a tablet computer for $233.56. Apps for the tablet cost 99¢ each. If Jasmine had $279 to spend on the tablet a

nd apps, what is the maximum number of apps she can buy?

1 answer:

Leto [7]3 years ago

7 0

45 games i just used a calculator will u please mark me brainiest hope this helps :)

You might be interested in

$14.95 dinner; 15% tip

Marysya12 [62]

$\frac{15}{100} \times 14.95 = \frac{3}{20} \times 14.95 \\ = 1.54$
hey hope this helps

8 0

3 years ago

Zoe is 16 years old. Her brother Luke is 3 years more than half her age. Write a numerical expression for Luke’s age.

Alenkasestr [34]

; Simplified =

Let "Zoe" = z

Let "Luke" = x

x = 16/2 + 3 is your equation

You're expression is

~

3 0

3 years ago

A student is asked to find a polynomial f(x) of degree four with the zeros 2, -3, 0, and -7. What factors would the student mult

lord [1]

Answer:

(x-2), (x+3),x and (x + 7)

Step-by-step explanation:

Here, the zeros of the polynomial are 2, -3, 0 and -7.

Let’s consider a case of a quadratic equation where x = 5 is a solution. This means that x + 5 is a factor of that quadratic equation.

Now, let’s apply same approach to this polynomial. If x = 2 is a solution, then x -2 is a factor. If x = -3, then, x + 3 is a factor. If x = 0, this means x itself is a solution and lastly, if x = -7 is a solution, that means x + 7 is a factor.

Thus, the factors to multiply together are; (x-2), (x+3),x and (x + 7)

4 0

3 years ago

AYOOO PLZ HELP ASAP!!!

tamaranim1 [39]

Answer:

B.

Step-by-step explanation:

Well we know that

$224=2^{5} *7$

so we can get the 2 outside of the radical

$x^{11} =(x^{5} )^{2} *x$

and we can get the x^2 outside too.

$y^8=y^5*y^3$

and we also can get y outside.

so we have:

$2x^{2}y\sqrt[5]{7xy^3}$

7 0

3 years ago

If n(A)=26, n(B)=41, and n(A ∩ B)=8, find n(A ∪ B).

miskamm [114]

n (AUB) = 59

Step-by-step explanation:

n(A U B) = n(A) + n(B) -n(A intersection B)

= 26+ 41- 8

= 59

8 0

3 years ago