Solutions
In Matrix we use initially based on systems of linear equations.The matrix method is similar to the method of Elimination as but is a lot cleaner than the elimination method.Solving systems of equations by Matrix Method involves expressing the system of equations in form of a matrix and then reducing that matrix into what is known as Row Echelon Form.<span>
Calculations
</span>⇒ <span>Rewrite the linear equations above as a matrix
</span>
⇒ Apply to Row₂ : Row₂ - 2 <span>Row₁
</span>
⇒ <span>Simplify rows
</span>
Note: The matrix is now in echelon form.
<span>The steps below are for back substitution.
</span>
⇒ Apply to Row₁<span> : Row</span>₁<span> - </span>5 Row₂
⇒ <span>Simplify rows
</span>
⇒ <span>Therefore,
</span>

<span>
</span>
Answer:
The answer is 2 and 1
Step-by-step explanation:
1+2=3 and 1 is half of 2
Answer:
<em>y = (x - 4) - 4 </em>
Step-by-step explanation:
m =
(- 2, - 10)
(4 , - 4)
m =
= 1
y + 4 = (x - 4) ⇒ <em>y = (x - 4) - 4</em>
Answer:
77 is a composite number
Step-by-step explanation:
41 = 1 × 41
77 = 1 × 77 = 7 × 11
83 = 1 × 83
89 = 1 × 89
97 = 1 × 97