9514 1404 393
Answer:
x^2 -5x +14 = 10^(2x +4)
Step-by-step explanation:
The relationship is ...
log(a) = b ⇔ a = 10^b
__
Using this with a=x^2-5x+14 and b=2x+4, we have ...
x^2 -5x +14 = 10^(2x +4)
_____
<em>Additional comments</em>
In plain text, the exponent needs parentheses, because superscript formatting is not available to tell what is and isn't part of the exponent.
The base of "log" is assumed to be 10 in high school algebra. In the larger world, "log" is often used in place of "ln" to mean the logarithm to base 'e'.
__
The one solution is approximately x = −1.32505947996.
Answer: A. inverse variation; xy = 20
ANSWER
Step-by-step explanation: Brainly
B) xy=20
Inverse because it is of the form y=k/x, intuitively you can see that as x increases y decreases, hence "inverse variation".
...............................................................................................................................................
Answer:
Option B is correct
Inverse variation , xy = 20
Step-by-step explanation:
Inverse variation states:
If
then the equation is in the form of:
or
xy = k ....[1]
As per the statement:
Given the data:
x : 2 4 8 12
y : 10 5 5/2 5/3
Let any value of x and y to find k:
x = 4 and y = 5
Substitute in [1] we have;
⇒20 = k
or
k = 20
then we get;
xy = 20
Check:
Substitute x = 12 and y = 5/3
⇒ true.
Therefore, the the data in the table represent a inverse variation and an equation to model the data in the table is, xy = 20
Answer:
The probability of selecting a male is 0.3151.
The events "male" and "driver" are not independent.
The correct option is B.
Step-by-step explanation:
The missing data is as follows:
Female Male Total
Driver 32759 11715 44474
Passenger 6534 6361 12895
Total 39293 18076 57369
The complete question is:
Determine P(male) and P(male|driver). Are the events "male" and "driver" independent?
Solution:
Compute the probability of selecting a male as follow:
Thus, the probability of selecting a male is 0.3151.
Compute the probability of selecting a male given that he is a driver as follows:
Two events, say A and B, are independent if:
P (A|B) = P(A)
Here, P (M|D) ≠ P (M)
Thus, the events "male" and "driver" are not independent.
Answer:
8.25y-14
Step-by-step explanation:
multiply the 4 into the bracket, add the like terms
Answer:
Therefore
ΔKLM ≅ Δ LKJ
Step-by-step explanation:
as you given a diagram where
∠JKL ≅∠MLK, ∠JLK≅ ∠MKL
As it is given
JK ≅ ML
KL ≅ LK
Therefore
ΔKLM ≅ Δ LKJ
