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marysya [2.9K]
3 years ago
13

Someone help. (Find the area of a rectangle with a lenght of 5a^2 b^4 and a width of (3ab^3)^2

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

All you do is just multiply them.

Step-by-step explanation:

5a^2 b^4(3ab^3)^2=

45(a^(4))(b^(10))

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Given cos(O)=3/5 and tan(O)
Valentin [98]

Answer:

Tan(O) = 4/3

Step-by-step explanation:

According to SOH CAH TOA

cos theta = adj/hyp

cosO = 3/4

adj = 3

hyp = 5

Get the opposite

Using pythagoras theorem

opp^2 = hyp^2-adj^2

opp^2 = 5^2 - 3^2

opp^2 = 25-9

opp^2 = 16

opp = 4

Tan (O) = opp/adj

Tan(O) = 4/3

Hence Tan(O) = 4/3

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6 0
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Nostrana [21]
The missing angle is 130 degrees.

The sum of all the angles of a hexagon equal 720 degrees. So, you'd add all the known angles together (this gives you 590), then subtract that from 720. Thus getting 130 degrees as a final answer.

I hope this helps!
5 0
3 years ago
Ursula makes $5 for every 1 dog she walks. In the relationship between dollars earned and dogs walked, ________ is the dependent
Stolb23 [73]

Answer:

B) Dollars earned is the dependent variable, which often called y

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