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marysya [2.9K]
3 years ago
13

Someone help. (Find the area of a rectangle with a lenght of 5a^2 b^4 and a width of (3ab^3)^2

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

All you do is just multiply them.

Step-by-step explanation:

5a^2 b^4(3ab^3)^2=

45(a^(4))(b^(10))

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6x + 12 -3x =51. <br> Step by step
Liula [17]
Start by combing like terms. You will get 3x+12=51. Now subtract 12 from both sides (3x=39). Divide both sides by 3 (x=13). The answer is 13.
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PLEASE HELP! BRAINIEST WILL BE MARK IF RIGHT!
DerKrebs [107]

Answer:

X int : 5

Y int : 15

Step-by-step explanation:

y=15

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3x=15

3/3 15/3

x=5

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sladkih [1.3K]

Answer:

think it's A (0,6) if not then idk maybe D

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rjkz [21]
A b c is the order of answers
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3 years ago
Can someone please help me ASAP.....
tester [92]

We have to start with a number x, compute f(x), and then use this result as input for g(x)

When you give x as input to f, it returns -x^2-1:

x\mapsto f(x)-x^2-1

Now, g(x)=x+5 simply means that g will return its input plus five.

In this case, the input is f(x), so we have

g(f(x))=f(x)+5 = -x^2-1+5=-x^2+4

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