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marysya [2.9K]
2 years ago
13

Someone help. (Find the area of a rectangle with a lenght of 5a^2 b^4 and a width of (3ab^3)^2

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
3 0

Answer:

All you do is just multiply them.

Step-by-step explanation:

5a^2 b^4(3ab^3)^2=

45(a^(4))(b^(10))

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#3 AB and AD are tangent to the circle centered at point C. Find the value of x. *
dezoksy [38]

Answer:

x=4

Step-by-step explanation:

tangent lines from the same point to a circle are congruent in length, so we can say that

5x+8 = 8x-4

5x -5x +8 = 8x - 5x -4

8 = 3x - 4

8+4 = 3x -4 + 4

3x = 12

3x/3 = 12/3

x=4

8 0
3 years ago
The parabola y=x^2 is shifted up by 8 units
dangina [55]

Answer:

It becomes y = x^2 + 8.

Step-by-step explanation:

The equation of the new parabola is y = x^2 + 8.

6 0
3 years ago
Helpppppppppppppppppppp
Ivan
I believe the answer is B and E
7 0
2 years ago
Write the product as a trinomial. (x + 2)(x + 4)
11111nata11111 [884]
Use: (a + b)(c + d) = ac + ad + bc + bd

(x+2)(x+4)=(x)(x)+(x)(4)+(2)(x)+(2)(4)=x^2+4x+2x+8=x^2+6x+8


Answer: d. x² + 6x +8

7 0
3 years ago
I need to know if this is correct
Law Incorporation [45]
Yes its right
hope this helps


7 0
2 years ago
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