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marysya [2.9K]
3 years ago
13

Someone help. (Find the area of a rectangle with a lenght of 5a^2 b^4 and a width of (3ab^3)^2

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

All you do is just multiply them.

Step-by-step explanation:

5a^2 b^4(3ab^3)^2=

45(a^(4))(b^(10))

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PLEASE HELP ME WITH MY MATH
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Answer:

Step-by-step explanation:

1)

y is 3 times more than x.

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X=1  Y=3

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Then just plot it as co-ordinates (x,y)

2)

Y is 1/4 of x. Divide by 4

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Len [333]

Answer:

2/8, 4,16

Step-by-step explanation:

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3 years ago
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CaHeK987 [17]

Answer:

167.2 m/sec

Step-by-step explanation:

Convert 602 km/hr to m/sec, as follows:

602 km       1000 m

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Recall that 1 hr = 3600 sec.  Convert 602,000 m/hr to m/sec:

602,000 m          1 hr

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2 years ago
Look at the right-angled triangle ABC.
Nikolay [14]

Answer:

∠x = 90°

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Step-by-step explanation:

The dimensions of the angles given are;

∠B = 32°

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∠A = 90°

∴ ∠B + ∠C = 90° which gives

32° + ∠C = 90°

∠C = 58°

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∴ ∠x + 90° = 180°

Hence;

∠x = 90°

∠x + ∠y + 32° = 180° (Sum of angles in a triangle)

∴ 90° + ∠y + 32° = 180°

∠y = 180 - 90° - 32° = 58°

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58° + ∠z +90° = 180°

∴ ∠z = 32°

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3 years ago
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astraxan [27]

Step-by-step explanation:

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