Someone help. (Find the area of a rectangle with a lenght of 5a^2 b^4 and a width of (3ab^3)^2
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Answer:
Step-by-step explanation:
Subtract x on both sides
Divide both sides by 3
To find the y-intercept, let x = 0
y = 0, therefore the function crosses the y-axis at the origin.
To find the x-intercept, let y = 0
x = 0, therefore the function crosses the x-axis at the origin too.
The slope of the function is -1/3, from the origin, go down 1 and right 3