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3 years ago

4x+y=14, 6x-3y=3 is the question

Mathematics

1 answer:

fomenos3 years ago

8 0

Answer:

if you are being asked what the values of the x and y variables are, x=5/2 and y=4

Step-by-step explanation:

In order to solve this problem you will want to isolate one of the two variables in both equations.

I isolated the y variable in both equations so you have:

4x+y=14, when you isolate the y variable, you will get: y=-4x+14

6x-3y=3, same procedure isolate y: 6x-3=3y, now simplify so you only have y: 2x-1=y.

Now that you have the two equations which a common variable, solve them by making the two equations equal to each other like so:

-4x+14=2x-1, now you want to have all the x variable terms on one side and all the constants on the other, you will add "4x" to each side of the equal sign and then add "1" to each side to leave you with: 15=6x

now divide both sides by 6 to obtain your x value: x=15/6 simplifies to 5/2

then plug your x-value into one of the two equations we made earlier:

y=2x-1

y=2(5/2)-1

y=5-1

y=4

now you have calculated the values of your x and y values

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For fun question

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Consider the function $f(x)=x^{1/3}$ , which has derivative $f'(x)=\dfrac13x^{-2/3}$ .

The linear approximation of $f(x)$ for some value $x$ within a neighborhood of $x=c$ is given by

$f(x)\approx f'(c)(x-c)+f(c)$

Let $c=64$ . Then $(63.97)^{1/3}$ can be estimated to be

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Since $f'(x)>0$ for $x>0$ , it follows that $f(x)$ must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function $f(x)$ . This means the estimated value is an overestimation.

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3 years ago

4x+y=14, 6x-3y=3 is the question​

4x+y=14, 6x-3y=3 is the question