Simplify 3/2n to 3n/2
3n/2 - 8/3 = 29/12
Add 8/3 to both sides
3n/2 = 29/12 + 8/3
Simplify 29/12 + 8/3 to 61/12
3n/2 = 61/12
Multiply both sides by 2
3n = 61/12 × 2
Simplify 61/12 × 2 to 122/12
3n = 61/6
Divide both sides by 3
n = 61/6/3
Simplify 61/6/3 to 61/6 × 3
n = 61/6 × 3
Simplify 6 × 3 to 18
<u>n = 61/18</u>
Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.

Multiply both sides by 100.


Divide both sides by 50.


The amount invested at 7% is
.
The amount invested at 8% is

The amount invested at 9% is

Thus, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
Answer:
3a=3
Step-by-step explanation:
ok there you go
Answer:
The answer is -15.
Step-by-step explanation:
1. 2x - 1
2. 2(-7) - 1
3. (-14) - 1
4. -15
By plugging in our x value, we are able to use PEMDAS to multiply 2 and the value of x and then, we subtract 1 from the value we got from step 3 to get -15.
Answer:
5, -1
Step-by-step explanation:
3x<10+8, 3x<18, x<6.