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Algebra
Factor
Factor the polynomial.
(
x
+
3
)
(
x
+
5
)
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()|[]ó
789≤
456/^×>∩∪
123-+÷<π∞
,0.%=
Factor
x
2
+
8
x
+
15
+
0
Regroup terms.
x
2
+
0
+
8
x
+
15
Add
x
2
and
0
.
x
2
+
8
x
+
15
Factor
x
2
+
8
x
+
15
using the AC method.
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Consider the form
x
2
+
b
x
+
c
. Find a pair of integers whose product is
c
and whose sum is
b
. In this case, whose product is
15
and whose sum is
8
.
3
,
5
Write the factored form using these integers.
(
x
+
3
)
(
x
+
5
)
Answer:
a) 26.2
b) 13.8
Step-by-step explanation:
You add all side lengths, which are given.
a) 9+4.1+9+4.1 = 26.2
b) 3.6+3+7.2 = 13.8
Missing term = –2xy
Solution:
Let us first find the quotient of
.


Taking common term xy outside in the numerator.

Both xy in the numerator and denominator are cancelled.

Thus, the quotient of
is
.
Given the quotient of
is same as the product of 4xy and ____.
× missing term
Divide both sides by 4xy, we get
⇒ missing term = 
Cancel the common terms in both numerator and denominator.
⇒ missing term = –2xy
Hence the missing term of the product is –2xy.