Solve the equation: 4) 12

Need help ASAP!! I'll give brainliest to correct answer!!!

erastovalidia [21]

Step-by-step explanation:

so...the answer is C.27.7m

4 0

3 years ago

Read 2 more answers

Having trouble solving this:

aliya0001 [1]

Answer:

3 $\frac{727}{1000}$

6 0

3 years ago

Jesses mom.gave him 45$ to buy snacks at school he spends 15 every two weeks

Black_prince [1.1K]

Answer:

ok?

whats the queston?

if its devide it is 3

Step-by-step explanation:

45=15x3

15/45=3

4 0

3 years ago

An artist receives 20% royalty on the retail price of his recordings. If he receives $36,000 in royalties, what is the dollar am

Mariulka [41]

Answer:

$180,000

Step-by-step explanation:

Because the artist gets 20% of the retail price, and 20% is equal to 1/5, the artist gets 1/5 of the retail price. So you do 36,000 times 5 to get the whole, original price.

4 0

4 years ago

<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cbegin%7Bbmatrix%7D%20%5Cbegin%7Barray%7D%20%7B%20l%20l%20%7D%20%7B%202%20%7D%20%

SVETLANKA909090 [29]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

In matrix multiplication, the number of columns in the 1st matrix is equal to the number of rows in the 2nd matrix.

$\left(\begin{matrix}2&3\\5&4\end{matrix}\right)\left(\begin{matrix}2&0&3\\-1&1&5\end{matrix}\right)$

Multiply each element of the 1st row of the 1st matrix by the corresponding element of the 1st column of the 2nd matrix. Then add these products to obtain the element in the 1st row, 1st column of the product matrix.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&&\\&&\end{matrix}\right)$

The remaining elements of the product matrix are found in the same way.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&3&2\times 3+3\times 5\\5\times 2+4\left(-1\right)&4&5\times 3+4\times 5\end{matrix}\right)$

Simplify each element by multiplying the individual terms.

$\left(\begin{matrix}4-3&3&6+15\\10-4&4&15+20\end{matrix}\right)$

Now, sum each element of the matrix.

$\large\boxed{\boxed{\left(\begin{matrix}1&3&21\\6&4&35\end{matrix}\right) }}$

7 0

3 years ago