1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SVETLANKA909090 [29]
3 years ago
11

26%20%7B%203%20%7D%20%5C%5C%20%7B%205%20%7D%20%26%20%7B%204%20%7D%20%5Cend%7Barray%7D%20%5Cend%7Bbmatrix%7D%20%5Cbegin%7Bbmatrix%7D%20%5Cbegin%7Barray%7D%20%7B%20l%20l%20l%20%7D%20%7B%202%20%7D%20%26%20%7B%200%20%7D%20%26%20%7B%203%20%7D%20%5C%5C%20%7B%20-%201%20%7D%20%26%20%7B%201%20%7D%20%26%20%7B%205%20%7D%20%5Cend%7Barray%7D%20%5Cend%7Bbmatrix%7D" id="TexFormula1" title=" \large\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}" alt=" \large\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}" align="absmiddle" class="latex-formula">
Solve using matrix multiplication rule. Please help! No spam.​
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
7 0

\huge \boxed{\mathbb{QUESTION} \downarrow}

\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}

In matrix multiplication, the number of columns in the 1st matrix is equal to the number of rows in the 2nd matrix.

\left(\begin{matrix}2&3\\5&4\end{matrix}\right)\left(\begin{matrix}2&0&3\\-1&1&5\end{matrix}\right)

Multiply each element of the 1st row of the 1st matrix by the corresponding element of the 1st column of the 2nd matrix. Then add these products to obtain the element in the 1st row, 1st column of the product matrix.

\left(\begin{matrix}2\times 2+3\left(-1\right)&&\\&&\end{matrix}\right)

The remaining elements of the product matrix are found in the same way.

\left(\begin{matrix}2\times 2+3\left(-1\right)&3&2\times 3+3\times 5\\5\times 2+4\left(-1\right)&4&5\times 3+4\times 5\end{matrix}\right)

Simplify each element by multiplying the individual terms.

\left(\begin{matrix}4-3&3&6+15\\10-4&4&15+20\end{matrix}\right)

Now, sum each element of the matrix.

\large\boxed{\boxed{\left(\begin{matrix}1&3&21\\6&4&35\end{matrix}\right) }}

You might be interested in
Please help :) Thank you
yKpoI14uk [10]

Answer:

the vertices are all labeled

a b c d and e

8 0
3 years ago
Read 2 more answers
What is 29+d=54;24,25,26
Yuliya22 [10]

d=54-29

d=25

this is the answer

4 0
3 years ago
Read 2 more answers
Only do question 4<br><br> 50 points<br><br> Topic: Percentage
Sergeu [11.5K]

Answer:

a 1

b 6

c 15

Step-by-step explanation:

101% 101/100 = 1 1/100

is 1  complete 100 grid and 1/100 of another grid so you will need 2 grids

589% 589/100 = 5 89/100

is 5 complete 100 grids and 89/100 of another grid so you will need 6 grids

1450% 1450/100 = 14 50/100

is 14 complete grids and 50/100 of another grid so you will need 15 grids

4 0
3 years ago
The area of a rectangle is 27 m^2 , and the length of the rectangle is 3 m less than twice the width. Find the dimensions of the
vagabundo [1.1K]
Let L be the length of the rectangle and W be the width. In the problem it is given that L=2W-3. It is also given that the area LW=27. Substituting in the length in terms of width, we have W(2W-3)=27 \\ 2W^2-3W-27=0 \\ (2W-9)(W+3)=0. Using the zero product property, 2W-9=0 \text{ or } W+3=0. Solving these we get the width W=4.5 \text{ or } -3. However, it doesn't make sense for the width to be negative, so the width must be \boxed{4.5 \text{ m}}. From that we can tell the length L=2(4.5)-3=\boxed{6 \text{ m}}. 
3 0
3 years ago
11.4÷35.7 answer estimated<br>(15 points)(brainliest included)<br>(incorrect answer=report)​
Gre4nikov [31]

Answer:

0.31932773109

Step-by-step explanation:

  • Set it up
  • Move the decimal point one place to the right for both of them
  • Then, do the long division
  • Keep adding zeros at the end until you have your answer
  • You can round it to 0.32 if you want
8 0
3 years ago
Other questions:
  • Mike drank more than half the juice in his glass.what fraction of the juice could Mike have drunk?
    6·1 answer
  • Shana wants to make a birthday cake for her mother. her old fashioned recipe calls for 3/12 Of a teaspoon of salt but she only h
    8·2 answers
  • The lunch platter at one restaurant costs $7. Write an equation that shows the total cost, c, of p people buying the lunch platt
    15·1 answer
  • SAFE<br> 42s + 32s + s - 42s
    8·1 answer
  • At the high school championship game, the Cougars beat the Lions 31 to 17. The total score came from 14 scoring plays. The scori
    9·1 answer
  • Y = – x – 6 y = x – 4 solve the system of equations using substition. HELP NEEDED IMMEDITLY!!!!!!!!
    5·2 answers
  • Use the diagram to find the missing measures.
    14·2 answers
  • Help me plz ASAP i will give brainliest.
    12·1 answer
  • PLZ HELP. MATH TEST PICK ABC OR D !
    12·2 answers
  • Find the surface area of the composite figure.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!