Answer:
3
Step-by-step explanation:
hope it helpz >-<
You can solve this by doing 8×8×6 which gives you 384. Since we are finding the volume, you would do length times with times height. Hope this helps :-)
It seems to me this just wants you to add the 3 equations.
2m + 2n +5p
Team A) 45 people
Team B) 55 people
A)There are two ways to solve this problem, finding the number of combinations possible for Team B, or the number of combinations possible for Team A.
Team A
It's a given that 20 mathematicians are on team A, which leavs the other 25 people for team A to be chosen from a pool of 80 (100- 20 mathletes)
80-C-25 = 80! / (25!/(80-25)!) =<span>363,413,731,121,503,794,368
</span>or 3.63 x 10^20
Solving using Team B
Same concept, but choosing 55 from a pool of 80 (mathletes excluded)
80-C-25 = 80! / (55!(80-55!) = 363,413,731,121,503,794,368
or 3.63 x 10^20
As you can, we get the same answer for both.
B)
If none of the mathematicians are on team A, then we exclude the 20 and choose 45:
80-C-45 = 80! / (45!(80-45)!) = <span>5,790,061,984,745,3606,481,440
or 5.79 x 10^22
Note that, if you solve from the perspective of Team B (80-C-35), you get the same answer</span>
When you see % next to a number, you multiply it by .01.
10 becomes .1
10.5 becomes .105
220*.1=22, so this is the 10% off
220*.105=23.1, so this is the 10.5% service charge.
220-22+23.1=$221.10 for the ticket.
