Answer:
Explanation:
volume of heptane= mass / density
volume of heptane = 37. 8 / .684
= 55.26 mL
volume of water = 34.7 / 1
= 34.7 mL or cc.
If l₁ be the length of heptane layer in the graduated cylinder
volume = cross sectional area x length or height of layer
π r² x l where r is radius of bore of the cylinder , l is height of liquid inside cylinder .
for heptane
π r² x l₁ = 55.26
3.14 x 1.54² x l₁ = 55.26
l₁ = 7.42 cm
for water
π r² x l₂ = 34.7
3.14 x 1.54² x l₂ = 34.7
l₂ = 4.65 cm
Combined height = l₁ + l₂
= 7.42 + 4.65
= 12.07 cm .
Ammonia gas will have a mass of 3.17grams.
HOW TO CALCULATE MASS:
- The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass.
- However, to calculate the number of moles present in the ammonia gas given in this question, we use the formula as follows:
where;
- P = pressure (atm)
- V = volume (L)
- n = number of moles (mol)
- R = gas law constant
- T = temperature
n = PV ÷ RT
n = (1.2 × 3.7) ÷ (0.0821 × 290)
n = 4.44 ÷ 23.81
n = 0.186mol
- Mass of ammonia gas = 3.17g
- Therefore, the mass of ammonia gas is 3.17grams.
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D. 18 as the elements in this group are the noble gases which exist as monoatomic elements with a full outer shell