Answer:
156.7mL
Explanation:
First we need to find the number of mole of He. This can be achieved by doing the following:
Mass of He from the question = 30g
Molar Mass of He = 4g/mol
Number of mole = Mass /Molar Mass
Number of mole of He = 30/4
Number of mole of He = 7.5moles
Now, we can obtain the volume as follows:
P = 1.15 atm
T = 20°C = 20 + 273 = 293K
R = 0.082atm.L/Kmol
n = 7.5moles
V =?
Recall: PV = nRT
V = nRT/P
V = (7.5 x 0.082 x 293)/1.15
V = 156.7mL
Therefore, the volume that can be filled to that pressure is 156.7mL
Answer is: the hydronium ion (H₃O⁺) concentration is greater than hydroxide ion (OH⁻)<span> concentration.
</span><span>Bases (more hydroxide ions than hydronium ions) turn red litmus paper blue and acids (more hydronium ions than hydroxide ions) turn blue
litmus paper red.
</span><span>Acids and bases have opposite properties and have the ability to
neutralize each other. Acids taste sour, give sharp stinging pain
in a wound and react with metals to produce hydrogen gas.</span>
- Standard reduction potential of Ag/Ag⁺ is 0.80 v and that of Cu⁺²(aq)/Cu⁰ is +0.34 V.
- The couple with a greater value of standard reduction potential will oxidize the reduced form of the other couple.
Ag⁺ will be reduced to Ag(s) and Cu⁰ will be oxidized to Cu²⁺
Anode reaction: Cu⁰(s) → Cu²⁺ + 2 e⁻ E⁰ = +0.34 V
Cathode reaction: Ag⁺(aq) + e → Ag(s) E⁰ = +0.80 V
Cell reaction: Cu⁰(s) + 2 Ag⁺(aq) → Cu⁺²(aq) + 2 Ag⁰(s)
E⁰ cell = E⁰ cathode + E⁰ anode
= 0.80 + (-0.34) = + 0.46 V
16.00 grams of oxygen
since in one mole the mass would be the molecular mass, which is found on the periodic table