Traffic flow at 1st Ave and High St is twice the traffic flow at 2nd ave and central. Compare the graph of the traffic flow at 1
1 answer:
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Answer:
(x, y) = (-2, -1) or (2, 1)
Step-by-step explanation:
Substitute for x in the first equation:
(2y)^2 +3(2y)y = 10
10y^2 = 10
y^2 = 1
y = ±1
x = 2y = ±2
Solutions are (x, y) = (-2, -1) or (2, 1).
Answer:
The expression will be simplified into
Step-by-step explanation:
It's like addition, when you multiply exponents that are on the same bases as each other.