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Ksenya-84 [330]
2 years ago
5

Traffic flow at 1st Ave and High St is twice the traffic flow at 2nd ave and central. Compare the graph of the traffic flow at 1

st Ave and High St to the graph of the traffic flow at 2nd Ave and Central over time
Mathematics
1 answer:
Anna007 [38]2 years ago
3 0

Answer:

The period of the graph of the traffic flow at 1st Ave and High St is half as long as the period of the graph of the traffic flow at 2nd Ave and Central.

Step-by-step explanation:

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How many acute angles did you measure in that figure?
olya-2409 [2.1K]

Answer:

4

Step-by-step explanation:

By having a clear glance at the picture , there are 4 acute angles. They are AMP , PMQ , BMQ & BMR

5 0
3 years ago
What is the common ratio for this geometric sequence?
Anastasy [175]

Answer:

<h2>A. 1/3</h2>

Step-by-step explanation:

\text{The common ratio of a geometric sequence}\ a_n:\\\\r=\dfrac{a_{n+1}}{a_n}\\\\\text{We divide next term by the previous one.}\\\\r=\dfrac{9}{27}=\dfrac{9:9}{27:9}=\dfrac{1}{3}\\\\r=\dfrac{3}{9}=\dfrac{3:3}{9:3}=\dfrac{1}{3}\\\\r=\dfrac{1}{3}\\\vdots

3 0
4 years ago
Read 2 more answers
1) Which equation could be used to estimate the population of Oak City in 10 years?
DaniilM [7]

Answer:

1) A

2) B

Step-by-step explanation:

For this problem we use exponential growth formulas

y = y_0(1 + r) ^ t if the population increases when t increases

y = y_0(1-r) ^ 2 If the population decreases when t increases

Where and is the population as a function of time, y_0 is the initial population, r is the growth rate, t is the time in years.

1) In this situation we have that y_0 = 48000, the growth is 2.4%, then r = 0.024 and t = 10 and the equation is:

y = 48000(1 + 0.024) ^ {10}

y = 48000(1.024) ^ {10} -------- Option A)

2) In this situation we have that y_0 = 82000, the decrease is 1.7%, then r = 0.017 and t = 5 and the equation is:

y = 82000(1-0.017) ^ 5

y = 82000(0.983) ^ 5 -------- Option B)

6 0
4 years ago
PLS HELP I DONT UNDERSTAND!!<br> What type of circle would you use when graphing x≥5
inna [77]

How to:

When graphing a linear inequality on a number line, use an open circle for "less than" or "greater than", and a closed circle for "less than or equal to" or "greater than or equal to".

For this problem:

For the number line, we would place a solid dot at −5 because the value is both greater than and equal too (≥) and then continue a line on the number line to the right of that point incorporating all values greater than −5

Answer:

<em><u>(image attached) </u></em>

<em><u>Look at the one showing your problem, the first one.</u></em>

<em><u>It's reverse of that since X is greater meaning the line goes the other way instead as shown in the second image.</u></em>

I HOPE I HELPED!! HAVE AN AMAZING DAY/NIGHT!!! PLEASE GIVE MY BRAINLIEST IF I HELPED YOU!!!!

-Sorry if I was unable to help you....I did my best!!

5 0
3 years ago
Which expression is equivalent to sec^2xcot^2x?
Lady_Fox [76]
\sec x=\dfrac{1}{\cos x}\\\\\cot x=\dfrac{\cos x}{\sin x}


\sec^2x\cot^2x=\dfrac{1}{\cos^2x}\cdot\dfrac{\cos^2x}{\sin^2x}=\dfrac{\cos^2x}{\cos^2x\sin^2x}=\dfrac{1}{\sin^2x}
8 0
3 years ago
Read 2 more answers
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