Answer:
b ≈ 9.5, c ≈ 14.7
Step-by-step explanation:
Using the Sine rule in Δ ABC, that is
= 
, substitute values
= 
( cross- multiply )
b × sin23° = 7 × sin32° ( divide both sides by sin23° )
b = 
≈ 9.5 ( to the nearest tenth )
Also
= 
= 
( cross- multiply )
c × sin23° = 7 × sin125° ( divide both sides by sin23° )
c = 
≈ 14.7 ( to the nearest tenth )
(a) From the histogram, you can see that there are 2 students with scores between 50 and 60; 3 between 60 and 70; 7 between 70 and 80; 9 between 80 and 90; and 1 between 90 and 100. So there are a total of 2 + 3 + 7 + 9 + 1 = 22 students.
(b) This is entirely up to whoever constructed the histogram to begin with... It's ambiguous as to which of the groups contains students with a score of exactly 60 - are they placed in the 50-60 group, or in the 60-70 group?
On the other hand, if a student gets a score of 100, then they would certainly be put in the 90-100 group. So for the sake of consistency, you should probably assume that the groups are assigned as follows:
50 ≤ score ≤ 60 ==> 50-60
60 < score ≤ 70 ==> 60-70
70 < score ≤ 80 ==> 70-80
80 < score ≤ 90 ==> 80-90
90 < score ≤ 100 ==> 90-100
Then a student who scored a 60 should be added to the 50-60 category.
Answer:
greater
Step-by-step explanation:
1.994 x 10^-23
-0.167 x 10^-23
1.827 x 10^-23
Correct answer is the second one.
