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2 years ago

Help me pls imma fail

Mathematics

1 answer:

KatRina [158]2 years ago

3 0

Answer:

Step-by-step explanation:

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Simplify i^5+i^6+ i^7+i^8<br><br> WILL GET 20 POINTS

Veronika [31]

I^5 + i^6 + i^7 + i^8

i^11 + i^15

i^26

therefore your answer is:

i^26

7 0

3 years ago

fond two consecutive odd integers whose sum is 36 which of the following equations could be used to solve the problem

Travka [436]

Answer:

17 is the answer.

Step-by-step explanation:

4 0

3 years ago

Find the arc length of a central angle of 7pi/3 in a circle whose radius is 3 inches.

skelet666 [1.2K]

$\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ \hrulefill\\ r=3\\ \theta =\frac{7\pi }{3} \end{cases}\implies s=3\cdot \cfrac{7\pi }{3}\implies s=7\pi$

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3 years ago

Read 2 more answers

The fictional rocket ship Adventure is measured to be 65 m long by the ship's captain inside the rocket.When the rocket moves pa

Gwar [14]

Answer:

a) t₀ = 1.73205 s

b) 1.0 C

Step-by-step explanation:

(A)

The time dilation (t) observed by an observer at rest relative to the time (t₀) measured by observer in motion is;

$t = \frac{t_0}{\sqrt{1 - \frac{V^2}{C^2}}}$

$t_0 = t \sqrt{1 - \frac{V^2}{C^2}}$ time measured by captain

⇒ $t_0 = 2.0 \sqrt{1 - \frac{0.5^2C^2}{C^2}}$ V = 0.5 c

⇒ t₀ = 1.73205 s

(B)

Speed of the light never exceeds by its real value. The speed of the light in any frame of reference is constant.

∵ It will be "1.0C" or just "C"

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2

Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

7 0

2 years ago