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2 years ago

Help me pls imma fail

Mathematics

1 answer:

KatRina [158]2 years ago

3 0

Answer:

Step-by-step explanation:

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Ayuda con mates por favor

QveST [7]

Answer:

a) $x = -1$ and $y = 5$ , b) $x = 2$ and $y = -1$ , c) $x = -2$ and $y = 1$ , d) $x = 2$ and $y = -9$ , e) $x = 2$ and $y = -2$ , f) $x = 2$ and $y = -1$ , g) $x = 2$ and $y = -1$ , h) $x = 1$ and $y = 2$ .

Step-by-step explanation:

Each system is solved as follows (Cada sistema es resuelto como sigue):

a) $2\cdot x + y = 3$ and $3\cdot x - y = -8$

$y = 3 - 2\cdot x$

$3\cdot x - 3 + 2\cdot x = -8$

$5\cdot x = -5$

$x = -1$

$y = 5$

b) $x - 2\cdot y = 4$ and $-x+3\cdot y = -5$

$x = 4 + 2\cdot y$

$-4-2\cdot y+3\cdot y = - 5$

$-4+y = -5$

$y = -1$

$x = 2$

c) $-2\cdot x + 5\cdot y = 9$ and $x - y = -3$

$x = y-3$

$-2\cdot y +6 +5\cdot y = 9$

$3\cdot y = 3$

$y = 1$

$x = -2$

d) $5\cdot x - 4\cdot y = 2$ and $3\cdot x + 2\cdot y = -12$

$3\cdot x + 2\cdot y = -12$

$6\cdot x + 4\cdot y = -24$

$4\cdot y = -6\cdot x -24$

$5\cdot x +6\cdot x +24 = 2$

$11\cdot x = -22$

$x = 2$

$y = -9$

e) $x + y = 0$ and $2\cdot x +3\cdot y = -2$

$y = -x$

$2\cdot x -3\cdot x = -2$

$-x = -2$

$x = 2$

$y = -2$

f) $3\cdot x + 5\cdot y = 1$ and $x + y = 1$

$y = 1 - x$

$3\cdot x + 5 - 5\cdot x = 1$

$-2\cdot x = -4$

$x = 2$

$y = -1$

g) $5\cdot x - 2\cdot y = 12$ and $4\cdot x + 3\cdot y = 5$

$x = \frac{12+2\cdot y}{5}$

$x = \frac{5-3\cdot y}{4}$

$\frac{12+2\cdot y}{5} = \frac{5-3\cdot y}{4}$

$4\cdot (12+2\cdot y) = 5\cdot (5-3\cdot y)$

$48 + 8\cdot y = 25 - 15\cdot y$

$23\cdot y = -23$

$y = -1$

$x = 2$

h) $7\cdot x + 8\cdot y = 23$ and $3\cdot x + 2\cdot y = 7$

$3\cdot x + 2\cdot y = 7$

$12\cdot x + 8\cdot y = 28$

$8\cdot y = 28 - 12\cdot x$

$7\cdot x +28-12\cdot x = 23$

$-5\cdot x = -5$

$x = 1$

$y = 2$

8 0

3 years ago

Solve equation (n-1)(n+6)(n+5)=0

Vika [28.1K]

Answer:
1, -6 and -5

Explanation:
To solve the equation means to get the values of n which satisfy the given equation.
The equation given is:
(n-1) (n+6) (n+5) = 0
This equation will be true if any of the terms (brackets) is equal to zero.
This means that:
either n-1 = 0 .............> n = 1
or n + 6 = 0 ................> n = -6
or n + 5 = 0 ................> n = -5

Hope this helps :)

5 0

3 years ago

Read 2 more answers

BRAINLIEST TO CORRECT HURRY

dalvyx [7]

5 16/25 is the greatest and -18/25 is the least if I'm correct

8 0

3 years ago

Help ASAP please ! Also explain how you got it

AlekseyPX

It is a right scalene because all of its measures are all different, which makes it a scalene. And what makes it a RIGHT scalene is that it has one right angle!

7 0

3 years ago

Read 2 more answers

A bridge hand is made up of 13 cards from a deck of 52. find the probability that a hand chosen at random contains at least 3 ki

Vlad [161]

1.
In total there are C(52, 13) ways that we can pick a hand, that is $\frac{52!}{13!39!}$

2.
P(a hand contains at least 3 kings)
=P(a hand contains exactly 3 kings)+P(a hand contains 4 kings)

3.
first let's find P(a hand contains exactly 3 kings):

P(a hand contains exactly 3 kings)
=n(a hand contains exactly 3 kings)/C(52, 13)

n(a hand contains exactly 3 kings)=C(4, 3)*C(48, 10)

where C(4,3) is the total number of ways we can pick 3 out of 4 kings,

C(48, 10) is the number of picking 10 letters to complete a hand, out of the 52-4=48 non-king cards.

so P(a hand contains exactly 3 kings)=[C(4, 3)*C(48, 10)]/C(52, 13)

4. with the same reasoning as in step 3:

P(a hand contains 4 kings)=n(a hand contains 4 kings)/C(52, 13)

= [C(4, 4)*C(48, 9]/C(52, 13)

5.

P(a hand contains at least 3 kings)
=P(a hand contains exactly 3 kings)+P(a hand contains 4 kings)

=[C(4, 3)*C(48, 10)]/C(52, 13)+ [C(4, 4)*C(48, 9)]/C(52, 13)

= $\frac{C(4, 3)*C(48, 10)+C(4, 4)*C(48, 9)}{C(52, 13)}$

= $\frac{4* \frac{48!}{10!38!} + \frac{48!}{9!39!}}{ \frac{52!}{13!39!} }$

simplify by 38! in the denominators and 48! in the numerators :

$\frac{4* \frac{1}{10!} + \frac{1}{9!39}}{ \frac{52*51*50*49}{13!39} } 

$

now simplify by 9! in all denominators:

$\frac{ \frac{4}{10}+ \frac{1}{39} }{ \frac{52*51*50*49}{13*12*11*10*39}}$

$\frac{ 0.426 }{ 9.7} =0.044$

4 0

4 years ago