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Mama L [17]
3 years ago
14

2yt1=2y+1. need help

Mathematics
1 answer:
faust18 [17]3 years ago
8 0
The answer is:
t=<span><span><span>2y</span>+1/</span><span>2<span>y

y=1/2t-2</span></span></span>
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Joan has 294 black marbles. Joan has 42 times more black marbles than Dan. How many black marbles does Joan has?
lara [203]
Joan has 294 marbles
dan has 7 marbles
5 0
3 years ago
3a+4b= c solve for b
Alina [70]

Answer:

b = (c - 3a)/4

Step-by-step explanation:

3a + 4b = c

4b = c - 3a

b = (c - 3a)/4

6 0
2 years ago
Find AC if A=25°, B=24°, and CB=14
photoshop1234 [79]
Answer is 38
25+14=38
8 0
3 years ago
Can you solve any of these geometry problem?
Fudgin [204]

Answer:

1. I don't know how to solve that sorry :(

2. B. It is a diameter

3. 30° = q

4. I don't know sorry :(

Step-by-step explanation:

1. I don't know how to solve that sorry :(

-----------------------------------------------------------

2. B. It is a diameter

------------------------------------

3. All triangles = 180°

180° = 60° + 90° + q

180° = 150° + q

180° - 150° = 150° - 150° + q

30° = q

180° = 60° + 90° + 30°

180° = 150° + 30°

180° = 180°

------------------------------------------

4. I don't know sorry :(

7 0
3 years ago
Fill in the missing statement and reason in the proof of the Alternate Exterior Angles Theorem.
ludmilkaskok [199]

Answer:

∠EGB and ∠AGF are congruent;

Transitive Property of Equality

Step-by-step explanation:

The vertical angles theorem is about the angles that are opposite to each other. These angles are formed when two lines cross each other

Vertical angles are congruent i.e their measures are equal

Look at the attached graph

Given:

AB // CD

E , G , H , F are col-linear

The line which contains points E , G , H , F is a transversal for the parallel lines AB and CD

∵ AB and EF intersected at point G

∴ m∠EGB = m∠AGF ⇒ by the vertical angles theorem

When lines AB and EF intersected at G they formed opposite angles like angles EGB and AGF, then angles EGB and AGF are congruent (  vertical angle theorem)

∵ AB // CD and EF is a transversal

∴ m∠AGF = m∠CHF (corresponding angles theorem)

Transitive Property of Equality:  if one angle is equal to two other angles, then the two other angles are equal

 Therefore, If a = b and b = c, then a = c

∵ m∠EGB = m∠AGF

∵ m∠AGF = m∠CHF

∴ m∠EGB = m∠CHF (transitive property theorem)

 ∠EGB and ∠AGF are congruent; Transitive Property of Equality

4 0
3 years ago
Read 2 more answers
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