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bezimeni [28]
2 years ago
13

PLEASE HELP! 50 POINTS

Mathematics
2 answers:
s2008m [1.1K]2 years ago
8 0

Answer:

x = 45

Step-by-step explanation:

→ Add all the angles together

x + 2x + 3x + 90 = 360

→ Simplify

6x + 90 = 360

→ Minus 90 from both

6x = 270

→ Divide by 6

x = 45

zubka84 [21]2 years ago
5 0

Hope you could understand.

If you have any query, feel free to ask.

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Answer:

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Step-by-step explanation:

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3 years ago
Karl’s math class is playing a number game. Each student is given a number card containing the numbers 1 to 6. The rules of the
Lena [83]

By finding the probability, we can expect that 2 out of the 30 students will win the prize.

<h3>How many of the 30 students will win the prize?</h3>

First, we should get the probability of winning this game.

Here the students select two numbers out of 6, just to make the calculations let's say that these numbers are 1 and 2.

Now, we need to get these two numbers in two balls. The probability of getting the ball with the number 1 out of the 6 balls is:

p = 1/6

The probability of getting the ball with the number 2 out of the remaining 5 balls (because we already got one) is:

q = 1/5

The joint probability is then:

P = 2*(1/6)*(1/5) = 1/15.

Where the factor 2 comes to take in account the permutations, for the case where we first draw the number 2 and then the number 1.

Then the expected number of students that will win is equal to the probability times the total number of students:

(1/15)*30 = 2

So out of the 30 students, we can expect that 2 will win.

If you want to learn more about probability:

brainly.com/question/25870256

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8 0
2 years ago
The equation of line a is y=3/4x-3 If line b runs parallel to line a and passes
katen-ka-za [31]

Answer:

y = -4/3 x - 1/3

Step-by-step explanation:

y = -4/3 x + b

5 = -4/3 (-4) + b

15 = 16 + 3b

b = -1/3

y = -4/3 x - 1/3

5 0
3 years ago
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lara31 [8.8K]

Answer:

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5 0
3 years ago
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
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