3rd 4th and 6th
all you have to do is substitute the ordered pair in variables place
dm me if you have any questions
-sheeda1st <span />
Answer:
Let x represent the smaller number and y represent the larger number
<u>For the first equation </u>
Four times a number added to 3 times a larger number is 31 is written as
4x + 3y = 31
Making y the subject we have
3y = - 4x + 31
Divide both sides by 3
That's
<u>For the second equation</u>
Seven subtracted from the larger number is equal to twice the smaller number is written as
y - 7 = 2x
Making y the subject
We have
<h3>y = 2x + 7</h3>
Hope this helps you
Answer:
The answer is True.
Step-by-step explanation:
- <u>Estimate the Answer Before Solving Having a general idea of a ballpark answer .</u>
- <u>Or the problem lets students know if their actual answer is reasonable or not.</u>
Answer:
The answer is C.
Step-by-step explanation:
Given formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height.
In this case, the initial postion is a platform 30ft above ground so h0=+30
The initial velocity is 38 ft/s straight up into the air so v0=+38
h(t)=-16t2+38t+30
When the object hits the ground, h=0.
h=-16t2+38t+30=0
Simplifying 8t2-19t-15=0
(8t+5)(t-3)=0
t=-5/8 or 3
As time cannot be -ve, t=3s. The answer is C.
