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3 years ago

11

How do you solve a system of linear equations by graphing?

1 answer:

Sergeeva-Olga [200]3 years ago

6 0

9514 1404 393

Explanation:

This is a self-answering question: you solve it by graphing the equations.

<em>The solution is where the lines intersect</em>. The point of intersection of the lines is the point that satisfies all the equations for the lines, hence is a solution to the system. If they do not intersect, there are no solutions. If the lines are coincident, there are an infinite number of solutions.

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The equations can be graphed by any of a number of methods. (My favorite is to let a graphing calculator do it.) The method of choice depends on the coefficients and the form the equations are given in. Methods of graphing are a topic for a more lengthy discussion.

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4 years ago

How many solutions are there for the equation y = x + 2?

defon

Answer:

Infinite solutions.

Step-by-step explanation:

If we let x = 1 then y = 3, or if x = 3 y = 5 and so on.

We can substitute any number of values of x and find the corresponding value of y so there are infinite solutions.

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3 years ago

What is the answer for this question?

Savatey [412]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

What is the density of an object having a mass of 25 g and a volume of 8.0 cm cubed

weqwewe [10]

Answer:

3.125 g/cm³.

Step-by-step explanation:

The formula for density/mass/volume is d = m/v, where d is density in grams per cm cubed, m is in grams, and v is in cm cubed.

In this case, m = 25 and v = 8.0.

d = 25 / 8.0

d = 25 / 8

d = 3.125.

So, the density of the object is 3.125 g/cm cubed.

Hope this helps!

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3 years ago

Let B1W2 denote the outcome that the first ball drawn is B1 and the second ball drawn is W2. Because the first ball is replaced

Sati [7]

Answer:

$\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\$

$W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}$

Step-by-step explanation:

$\text{If an urn contains two blue balls} (denoted \:B_1 \:and \:B_2) \text{and three white balls}$ , $(denoted \:W_1, W_2, \:and\: W_3)$

If One ball is drawn, its color is recorded, and it is replaced in the urn. Then another ball is drawn and its color is recorded.

The 25 Possible outcomes of this experiment are listed below:

$\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\$

$W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}$

The tree diagram of this event is also attached.

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3 years ago