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Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
The equation in slope intercept form is,. The given equation is obtained by comparing the standard equation of the straight line.
<h3>What is a slope of a straight line?</h3>
A straight line is a combination of endless points joined on both sides of the point.
The slope 'm' of any straight line is given by:
The given equation is;
1.25 (25) = 31.25
31.25=1.25 (25)
The standard equation of the slope intercept form. is;
On comparing the given equation with the above equation, we get;
y=31.25
m=1.25
x=25
c=0
The equation in slope intercept form is;
Hence, the above equation is the slope intercept form.
Learn more about the slope of the straight line;
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