Answer:
m < 1 = 18°
Step-by-step explanation:
If <ABD = 72°, and m < 2 is three times the measure of m < 1, then:
Let < ABC = m < 1 = x
< CBD = m < 2 = 3x
We can set up the following formula, since the sum of the measures of angles < 1 and < 2 is equal to <ABD (72°):
m < 1 + m < 2 = < ABD
x + 3x = 72°
Add like terms:
4x = 72°
Divide both sides by 4 to solve for x:
x = 18
Since x = 18, and m < 1 = x , then m < 1 = 18°.
And since m < 2 = 3x, then m < 2 = 3(18°) = 54°.
Let's check to see whether we derived the correct answers by plugging in the values of m < 1 and m < 2 into the established formula:
m < 1 + m < 2 = < ABD
18° + 54° = 72°
72° = 72° (True statement).
Please mark my answers as the Brainliest if my explanations were helpful :)
Answer:
29.56
Step-by-step explanation:
From the given diagram
x = hypotenuse
27 = adjacent
Using SOH CAH TOA identity
cos theta = adj/hyp.
Cos 24 = 27/x
x = 27/cos24
x = 29.56
Hence the value of x to the hundredth place is 29.56
Can you give the call numbers. its hard to arrange them without actually knowing what they are
Answer: 1.79 inches
Step-by-step explanation: took the quiz
ANSWER: A. 46
SOLUTION
Given that Q is equidistant from the sides of TSR
m∠TSQ = m ∠QSR
To solve for x
m∠TSQ = 3x + 2
m ∠QSR = 8x – 33
Since m∠TSQ = m ∠QSR
3x + 2 = 8x – 33
Add 33 to both sides
3x + 2 + 33 = 8x – 33 + 33
3x + 35 = 8x
8x = 3x + 35
Subtract 3x from both sides
8x – 3x = 3x – 3x + 35
5x = 35
Divide both sides by 5
x = 7
Since m∠TSQ = 3x + 2, and x = 7
m∠TSQ = (3*7) + 2
m∠TSQ = 21 + 2
m∠TSQ = 23
To solve for RST
Given that Q is equidistant from the sides of RST
m∠RST = m∠TSQ + m ∠QSR
Since m∠TSQ = m ∠QSR
m∠RST = 2m∠TSQ = 2m ∠QSR
Ginen, m∠RST = 2m∠TSQ
m∠TSQ = 23
m∠RST = 2(23)
m∠RST = 46
