Question

Rectangle ABCD translates 4 units down and 2 units to the right to form rectangle A'B'C'D'. The vertices of rectangle ABCD are labeled in alphabetical order going clockwise around the figure. If AB = 3 units and AD = 5 units, what is the length of B'C'?

Answer 1

The length of B'C' in the rectangle A'B'C'D' = 9 units.

Step-by-step explanation:

step 1 :

Draw a rectangle with vertices ABCD in clockwise direction.

where, AB and DC are width of the rectangle ABCD.

            AD and BC are length of the rectangle ABCD.

step 2 :

Now,

The length of the rectangle is AD = 5 units and

The width of the rectangle is AB = 3 units.

step 3 :

Draw another rectangle with vertices A'B'C'D' extended from vertices of the previous rectangle ABCD.

step 3 :

The length of the new rectangle is A'D' which is 4 units down from AD.

∴ The length of A'D' = length of AD + 4 units = 5+4 = 9 units

step 4 :

Since B'C' is also the length of the rectangle A'B'C'D', then the measure of B'C' is 9 units.