Y = (2/3)x + 6
3y - 5x = 9
find an expression for y from the second equation:-
y = (5/3)x + 3
Now substitute this for y in the first equation:-
(5/3) x + 3 = (2/3)x + 6 Now solve for x:-
(5/3)x - (2/3)x = 6 - 3
x = 3
Now plug x = 3 into the second equation to find the value of y:_
3y - 5(3) =9
3y = 15+9 = 24
y = 8
So the solution is x = 3, y = 8
written as a set this is {3,8}.
.465
i hope im right and
i hope i helped.
Yo im sorry but I can’t help I’m jus trying to answer questions so I can ask them
Slope 2/1, y intercept is 6, equation is f(x)=6-2x
5.2/0.052 is 100, and 100 is 10^2, so the missing divisor is 10^2
