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kondaur [170]
2 years ago
5

Hi Guys,

Mathematics
1 answer:
Leto [7]2 years ago
7 0
<h2>GOOD LUCK IN THE TEST!!!!!!!</h2>

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kondor19780726 [428]

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1 option or last option are the best choices sorry if I'm wrong.

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3 years ago
The new ointment was applied to four locations, and a control was applied to the other four. How many different choices were the
lubasha [3.4K]

Answer:

there are 70 possible choices for the four locations to apply the new ointment

Step-by-step explanation:

Since we have a total of 8 locations ( 4 to the new ointment and 4 to the control) ,  each one can be chosen and since the order of the locations that are chosen for the new ointment is not relevant  , then we know that the number of choices is given by the number of combinations of 4 elements in 8

number of combinations = 8 possible locations to the first ointment * 7 possible locations to the second ( since the first one was already located) * 6 to the third * 5 locations for the fourth / number of times the same combination is repeated ( the same locations but in different positions) = 8*7*6*5 / (4 possible positions for the first ointment* 3 possible positions to the second ointment (since the first one was already located * 2 possible positions of the third * 1 possible position of the fourth)

therefore

number of combinations = 8*7*6*5/(4*3*2*1 ) = 8!/((8-4)!*4!) = 70 possible combinations

thus there are 70 possible choices for the four locations to apply the new ointment

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3 years ago
Jason plans to pay the water bill with two equal payments. Water:35$ Gas 14$
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