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vichka [17]
3 years ago
9

In a study of the progeny of rabbits, Fibonacci (ca. 1170-ca. 1240) encountered the sequence now bearing his name. The sequence

is defined recursively as follows.
an + 2 = an + an + 1, where a1 = 1 and a2 = 1.

(a) Write the first 12 terms of the sequence.

(b) Write the first 10 terms of the sequence defined below. (Round your answers to four decimal places.)

bn =

an + 1/

an, n ? 1.

(c) The golden ratio ? can be defined by

limn ? In a study of the progeny of rabbits, Fibonacci (cbn = ?

, where

? = 1 + 1/?. Solve this equation for ?. (Round your answer to four decimal places.)
Mathematics
1 answer:
expeople1 [14]3 years ago
6 0

The question in part c is not clear, nevertheless, part a and part b would be solved.

Answer:

a. The first twelve terms are:

1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144.

b. The first ten terms are:

1.000, 1.000, 1.500, 1.667, 1.600, 1.625, 1.615, 1.619, 1.618, 1.618.

Step-by-step explanation:

a. Given

an + 2 = an + an + 1

where a1 = 1 and a2 = 1.

a3 = a1 + a2

= 2

a4 = a2 + a3

= 3

a5 = a3 + a4

= 5

a6 = a5 + a4

= 8

a7 = a6 + a5

= 13

a8 = a7 + a6

= 21

a9 = a8 + a7

= 34

a10 = a9 + a8

= 55

a11 = a10 + a9

= 89

a12 = a11 + a10

= 144

The first twelve terms are:

1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144.

(b)

Given

bn = an+1/an

b1 = a2/a1

= 1/1 = 1.000

b2 = a3/a2

= 2/1 = 1.000

b3 = a4/a3

= 3/2 = 1.500

b4 = a5/a4

= 5/3 = 1.667

b5 = a6/a5

= 8/5 = 1.600

b6 = a7/a6

= 13/8 = 1.625

b7 = a8/a7

= 21/13 = 1.615

b8 = a9/a8

= 34/21 = 1.619

b9 = a10/a9

= 55/34 = 1.618

b10 = a11/a10

= 89/55 = 1.618

The first ten terms are:

1.000, 1.000, 1.500, 1.667, 1.600, 1.625, 1.615, 1.619, 1.618, 1.618.

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Consider the following argument. If I get a Christmas bonus, I'll buy a stereo. If I sell my motorcycle, I'll buy a stereo. ∴ If
Nuetrik [128]

Answer:

p → r valid, proof by division into cases

q → r

∴ p ∨ q → r

Step-by-step explanation:

Let

p = "if I get a Christmas bonus,"

q = "if I sell my motorcycle,"

and

r = "I'll buy a stereo."

This can be written as:

If I get a Christmas bonus, I'll buy a stereo

p → r

If I sell my motorcycle, I'll buy a stereo

q → r

∴ If I get a Christmas bonus or I sell my motorcycle, then I'll buy a stereo.

∴ p ∨ q → r

To prove this argument we partition the argument into a group of smaller statements that together cover all of the original argument and then we prove each of the smaller statements. If you see the conclusion ∴ p ∨ q -> r so if the conclusion contains a conditional argument of form "If A1  or A2 or... or An then C ”, then we prove "If A1 then C", "If A2 then C" and so on upto "If An then C" . This depicts that the conclusion  C is true no matter which if the Ai holds true. This method is called proof by division into cases. In the given example, this takes the form:

p → r

q → r

p ∨ q

∴ r

Since proof by division into cases is an inference rule thus given argument is valid. Lets make a truth table to show if this argument is valid

p   q   r   p ∨ q   p → r    q → r    p ∨ q → r

0   0   0     0        1           1             1

0   0   1      0        0          0            0

0   1    0     1         1           0            0

0   1    1      1         0          1               1

1    0   0     1         0          1             0    

1    0   1      1         1           0            1    

1    1    0     1         0          0            0    

1    1    1      1         1           1              1    

An argument is valid if all of the premises are true, then the conclusion is true. So the truth table shows that the conclusion is true i.e. 1 where all premises are true i.e. 1. So the argument is valid.

Hence

p → r valid, proof by division into cases

q → r

∴ p ∨ q → r

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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A rectangle has breadth 5cm and area 40cm². Its length is equal to the height of a triangle of base 18cm. Find the area of the t
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