Question

A fair spinner has 9 equal sections: 2 red, 3 blue and 4 green.

Answer 1

Answer:

The Probability of not getting two consecutive reds is 0.9506

Step-by-step explanation:

Number of sections = 9

Number of red sections = 2

Number of blue sections = 3

Number of green sections = 4

Probability of getting two consecutive reds = $\frac{2}{9} \times \frac{2}{9}=\frac{4}{81}$

So,The Probability of not getting two consecutive reds =$1- \frac{4}{81}=\frac{77}{81}=0.9506$

Hence The Probability of not getting two consecutive reds is 0.9506