A. Let a, b, c be positive integers and suppose that

Mathematics

1 answer:

kodGreya [7K]3 years ago

5 0

Answer:

Step-by-step explanation:

B) if x and x’ are both solution then we have that

mi | x-x’ for every i.

By a) we have that m1m2...mk| x-x’, so x and x’ are equal by mod od m1m2...mk.

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Given:

The matrix multiplication

$\begin{bmatrix}4&5&6\\1&2&3\end{bmatrix}\begin{bmatrix}10\\20\\30\end{bmatrix}$

To find:

The order of resulting matrix.

Solution:

We know that, if order of first matrix is $m_1\times n_1$ and the order of second matrix is $m_2\times n_2$ , then the order of these two matrices is $m_1\times n_2$ .

We have,

$\begin{bmatrix}4&5&6\\1&2&3\end{bmatrix}\begin{bmatrix}10\\20\\30\end{bmatrix}$

Here, the order of first matrix is $2\times 3$ and the order of the second matrix is $3\times 1$ . So, the order of the second matrix is $2\times 1$ . It is also written are 2 by 1.