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2 years ago

Read what on the image and it is so easy

Mathematics

1 answer:

vova2212 [387]2 years ago

7 0

F - 1.47

The largest box represents 100 small cubes or 1. The four pillars represent 10 and there is four of them so it is 40. Then, the individual cubes are 7. So, 1.47.

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A 15 pound bag of ice costs $ 1.80. Give the unit rate.

Vaselesa [24]

We can use a rule of three simple, direct proportion to solve this problem.
15 pounds correspond to $1.80, then the question is to find the price of one pound, the called unit rate. We state the rule of three:
15 pound ----> $1.80
1 pound -----> x
x = (1)(1.80)/15
x = 0.12
Therefore, each pound costs $0.12 that is the unit rate in pounds

7 0

3 years ago

A flowerpot has a diameter of 15 centimeters. Which expression can be used to find its circumference, C, in centimeters?

Elena-2011 [213]

The answer is C because the formula is 2 x pai x radius

4 0

3 years ago

Which triangles (if any) can be shown to be congruent using a rotation? A) 1 and 2 B) 2 and 3 C) 1 and 3 D) none

Talja [164]

The answer is 1 and 3.

6 0

3 years ago

Find the other endpoint of the line segment with the given endpoint and midpoint: Endpoint - (1, 3) Midpoint - (0, 0)

Kobotan [32]

Answer:

The other endpoint of the line segment = (-1, -3)

Step-by-step explanation:

A segment has:

Endpoint: (1, 3)

Midpoint: (0, 0)

Let (x, y) be the other endpoint of the line segment

$\frac{\left(1\:+\:x\right)}{2}=0$

$\mathrm{Multiply\:both\:sides\:by\:}2$

$\frac{2\left(1+x\right)}{2}=0\cdot \:2$

$1+x=0$

$x=-1$

$\frac{\left(3+y\right)}{2}=0$

$\mathrm{Multiply\:both\:sides\:by\:}2$

$\frac{2\left(3+y\right)}{2}=0\cdot \:2$

$3+y=0$

$y=-3$

Therefore, the other endpoint of the line segment = (-1, -3)

4 0

3 years ago

Hi, can you help to find (all the roots/zeros), please!!!

OLga [1]

Solution

Given the quadratic equation

$x^2-2x-38=0$

we need to find the zeros of the equation

To do that, we use the completing the square method

Step 1. Add 38 to both sides

$\begin{gathered} \Rightarrow x^2-2x-38+38=38 \\ \\ \Rightarrow x^2-2x=38 \end{gathered}$

Step 2: add the square of half of the coefficient of x to both sides

That is;

$\begin{gathered} \Rightarrow x^2-2x+(\frac{1}{2}\cdot(-2))^2=38+(\frac{1}{2}\cdot(-2))^2 \\ \\ \Rightarrow x^2-2x+1=38+1 \\ \\ \Rightarrow x^2-2x+1=39 \\ \\ \Rightarrow(x-1)^2=39 \end{gathered}$

Step 3: Simplify the above expression;

$\begin{gathered} \Rightarrow x-1=\pm\sqrt[]{39} \\ \\ \Rightarrow x=1\pm\sqrt[]{39} \end{gathered}$

4 0

11 months ago