Answer:
In mathematics, equality is a relationship between two quantities or, more generally two mathematical expressions, asserting that the quantities have the same value, or that the expressions represent the same mathematical object. The equality between A and B is written A = B, and pronounced A equals B.[1][2] The symbol "=" is called an "equals sign". Two objects that are not equal are said to be distinct.
Step-by-step explanation:
For example:
{\displaystyle x=y}x=y means that x and y denote the same object.[3]
The identity {\displaystyle (x+1)^{2}=x^{2}+2x+1}{\displaystyle (x+1)^{2}=x^{2}+2x+1} means that if x is any number, then the two expressions have the same value. This may also be interpreted as saying that the two sides of the equals sign represent the same function.
{\displaystyle \{x\mid P(x)\}=\{x\mid Q(x)\}}{\displaystyle \{x\mid P(x)\}=\{x\mid Q(x)\}} if and only if {\displaystyle P(x)\Leftrightarrow Q(x).}{\displaystyle P(x)\Leftrightarrow Q(x).} This assertion, which uses set-builder notation, means that if the elements satisfying the property {\displaystyle P(x)}P(x) are the same as the elements satisfying {\displaystyle Q(x),}{\displaystyle Q(x),} then the two uses of the set-builder notation define the same set. This property is often expressed as "two sets that have the same elements are equal." It is one of the usual axioms of set theory, called axiom of extensionality.[4]
Step-by-step explanation:
Circumference of a circle is 2piR
Here R is 3 cm
So C=2pi(3)
C=6pi cm
Answer: 12.4 + 1.1x + 2.2x^2 + 2.3x^3
Step-by-step explanation:
add the like variables
Answer:
I'm not sure, but I think they spend 2$ for each
Step-by-step explanation:
The total items they buyed was 45. The total amount of money they spend was 95. 95 divided by 45 is 2.111111111111111111111 . So if you find 2 as one of your options, that's probably it.
The solution would be like
this for this specific problem:
189 x .0688
= 12.8 + 189 = 201.8<span>
(4 x 360)
x .06 = 86.4
(29 x 2)
+ 86.4 = 144.4
201.8 +
144.4 = $346.2</span>
I am hoping that this answer has
satisfied your query and it will be able to help you in your endeavor, and if
you would like, feel free to ask another question.
