Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate
L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
12/8=
6/4=
3/2
Your answer in simplest form would be 3/2
Answer:
x-axis from -20 to 5; y-axis from -80 to 80
Step-by-step explanation:
The attached graph shows my choice for a viewing window. The closest approximation among your answer choices is ...
x: -20 to 5
y: -80 to 80 . . . . . choice A
Answer:
The volume of water that remains on the cone is 523.6 cm³
Step-by-step explanation:
To solve this problem you have to keep in mind the formules that describes the volume of a cone and the volume of a sphere.
Volume of a cone = (πr²h)/3
Volume of a sphere = (4/3)πr³
So, if the base of the cone has a diameter of 10 cm, its radius is 5 cm. Its altitude is 10 cm. ⇒Volume = (πr²h)/3 ⇒ Volume = [π(5²)10) ⇒
Volume = 785.4 cm³. This is the initial volume of water.
Now if the sphere fits in the cone and half of it remains out of the water, the other half is inside the cone. Estimating the volume of the sphere and dividing it by two, you find the volume of water that was displaced.
Volume of a sphere = (4/3)πr³, here the radius is the same of the base of the cone (5 cm).
⇒ Volume = (4/3)π(5³) ⇒ Volume = 523.6 cm³ ⇒ The half of this volume is 261.8 cm³. This is the volume of water displaced.
⇒ The volume of water that remains on the cone is 523.6 cm³ (785.4 cm³- 261.8 cm³)
She made 16 cups of punch.
