Hmm is there supposed to be a picture cuz if there is than can i see it if not then i guess your right
By converting into parametric equations,
<span>{<span><span>x<span>(θ)</span>=r<span>(θ)</span><span>cosθ</span>=<span>cos2</span>θ<span>cosθ</span></span><span>y<span>(θ)</span>=r<span>(θ)</span><span>sinθ</span>=<span>cos2</span>θ<span>sinθ</span></span></span></span>
By Product Rule,
<span>x'<span>(θ)</span>=−<span>sin2</span>θ<span>cosθ</span>−<span>cos2</span>θ<span>sinθ</span></span>
<span>x'<span>(<span>π2</span>)</span>=−<span>sin<span>(π)</span></span><span>cos<span>(<span>π2</span>)</span></span>−<span>cos<span>(π)</span></span><span>sin<span>(<span>π2</span>)</span></span>=1</span>
<span>y'<span>(θ)</span>=−<span>sin2</span>θ<span>sinθ</span>+<span>cos2</span>θ<span>cosθ</span></span>
<span>y'<span>(<span>π2</span>)</span>=−<span>sin<span>(π)</span></span><span>sin<span>(<span>π2</span>)</span></span>+<span>cos<span>(π)</span></span><span>cos<span>(<span>π2</span>)</span></span>=0</span>
So, the slope m of the curve can be found by
<span>m=<span><span>dy</span><span>dx</span></span><span>∣<span>θ=<span>π2</span></span></span>=<span><span>y'<span>(<span>π2</span>)</span></span><span>x'<span>(<span>π2</span>)</span></span></span>=<span>01</span>=0</span>
I hope that this was helpful.
Answer:
Step-by-step explanation:
In slope intercept form y = mx + b
We have the y intercept already so our equation becomes y = mx -3. Now we need to figure out the slope, we do this by subtracting the y values from both points and the x values from both points:
-3 - 0 = -3
0 - 4 = -4
Slope = -3/-4 the negatives cancel and now we have 3/4 as the slope.
Now the equation is y = 3/4x -3
Double checking by inputting values such as x = 0 we now get (0, -3) which is correct and if the x-intercept is 4 then it should give us a y value of 0 which = (4,0). Yep! This is the correct linear equation for the line described
Is there any more to the question? I cant give an answer based off of that!!